Answer:
The possible range of wavelengths in air produced by the instrument is 7.62 m and 0.914 m respectively.
Explanation:
Given that,
The notes produced by a tuba range in frequency from approximately 45 Hz to 375 Hz.
The speed of sound in air is 343 m/s.
To find,
The wavelength range for the corresponding frequency.
Solution,
The speed of sound is given by the following relation as :
Wavelength for f = 45 Hz is,
Wavelength for f = 375 Hz is,
So, the possible range of wavelengths in air produced by the instrument is 7.62 m and 0.914 m respectively.
Answer:
The magnitude is:
The direction of E is in the negative x-direction.
Explanation:
The electric field equation is:
Where:
- Q is the charge (we can choose the electron or the proton)
- r is the distance (in our case is at the midpoint 973/2 nm)
- k is the Coulomb constant ()
Using the electron charge ()
The magnitude is:
The direction of E is in the negative x-direction.
I hope it helps you!