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2 years ago

What are the two main types of energy?

Physics

1 answer:

djyliett [7]2 years ago

7 0

Answer:

Fourth option

Explanation:

They're many different types of energy, from chemical and mechanical to heat and solar energy. But the two most basic types of energy are "kinetic and potential energy" or the fourth option. Kinetic energy is the energy an object has when it is in motion, while potential energy is the energy an object has when it's as rest. These two specific types of energies are the most basic and you can even convert them into many different types of energies, like heat or electrical energy.

Hope this helps.

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A frog leaps with a displacement equal to vector u and then leaps with a displacement equal to vector v, as

denpristay [2]

Answer:

The answer is B on khan academy

Explanation:

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2 years ago

What is Virtual Lab and what does people use it for and why they use it?

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2 years ago

2. A hanging wind-chime on a calm day would have kinetic or potential energy?

rjkz [21]

Answer:

it would have potential energy

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2 years ago

How was Mendeleev's table different from Meyer's table? A. Mendeleev did not arrange according to chemical properties. B. Meyer

olya-2409 [2.1K]

Answer: C. Meyer did not leave gaps while Mendeleev did.

Explanation: Mendeleev's table was table different from Meyer's table because Meyer did not leave gaps while Mendeleev did.

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2 years ago

If a car is taveling with a speed 6 and comes to a curve in a flat road with radius ???? 13.5 m, what is the minumum value the c

Lemur [1.5K]

Answer:

$\mu_s \geq 0.27$

Explanation:

The centripetal force acting on the car must be equal to mv²/R, where m is the mass of the car, v its speed and R the radius of the curve. Since the only force acting on the car that is in the direction of the center of the circle is the frictional force, we have by the Newton's Second Law:

$f_s=\frac{mv^{2}}{R}$

But we know that:

$f_s\leq \mu_s N$

And the normal force is given by the sum of the forces in the vertical direction:

$N-mg=0 \implies N=mg$

Finally, we have:

$f_s=\frac{mv^{2}}{R} \leq \mu_s mg\\\\\implies \mu_s\geq \frac{v^{2}}{gR} \\\\\mu_s\geq \frac{(6\frac{m}{s}) ^{2}}{(9.8\frac{m}{s^{2}})(13.5m) }\\\\\mu_s\geq0.27$

So, the minimum value for the coefficient of friction is 0.27.

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3 years ago