Answer:
sorry I don't understand this language
Ok, I think this is right but I am not sure:
Q = ϵ
0AE
A= π π
r^2
=(8.85x10^-12 C^2/Nm^2)
( π π (0.02m)^2)
(3x10^6 N/C) =3.3x10^-8 C = 33nC N = Q/e = (3.3x10^-8 C)/(1.60x10^-19 C/electron) = 2.1x10^11 electrons
Answer:
2.47 s
Explanation:
Convert the final velocity to m/s.
We have the acceleration of the gazelle, 4.5 m/s².
We can assume the gazelle starts at an initial velocity of 0 m/s in order to determine how much time it requires to reach a final velocity of 11.1111 m/s.
We want to find the time t.
Find the constant acceleration equation that contains all four of these variables.
Substitute the known values into the equation.
- 11.1111 = 0 + (4.5)t
- 11.1111 = 4.5t
- t = 2.469133333
The Thompson's gazelle requires a time of 2.47 s to reach a speed of 40 km/h (11.1111 m/s).
Answer:
0.56 km/s
Explanation:
We will define a single system of units for measurement, for this case meters per second [m/s]. That is, we must convert the rest of units such as centimeters per second and kilometers per second to meters per second.
![560[\frac{cm}{s}]*(\frac{1m}{100cm} )=5.6[m/s]\\0.56[\frac{km}{s}]*(\frac{1000m}{1km} )=560[m/s]](https://tex.z-dn.net/?f=560%5B%5Cfrac%7Bcm%7D%7Bs%7D%5D%2A%28%5Cfrac%7B1m%7D%7B100cm%7D%20%29%3D5.6%5Bm%2Fs%5D%5C%5C0.56%5B%5Cfrac%7Bkm%7D%7Bs%7D%5D%2A%28%5Cfrac%7B1000m%7D%7B1km%7D%20%29%3D560%5Bm%2Fs%5D)
Therefore the speed of 0.56 [km/s] is the greatest of all
