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pashok25 [27]
3 years ago
15

A math test is worth 100 points and has 38 problems. Each problem is worth either 5 points or 2 points. How many problems of eac

h point value are on the test?
Mathematics
1 answer:
serious [3.7K]3 years ago
5 0
Give me brainkiser to  answer

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What is the answer?
arsen [322]
10 equal pieces I think
6 0
4 years ago
What is the equation of the line that passes through the points (–12, –8) and (–17, –16)?
horsena [70]

Answer:

<em>firstly</em><em> find</em><em> the</em><em> gradient</em><em> given</em><em> by</em><em> the</em><em> equation</em>

<em>m=</em><em>y2-y1</em><em>/</em><em>x2-x1</em>

<em>in this </em><em>case</em><em> </em><em>x1 </em><em>is </em><em>-</em><em>1</em><em>2</em><em>,</em><em>x2 </em><em>is </em><em>-</em><em>1</em><em>7</em><em>,</em><em> </em><em>y1 </em><em>is </em><em>-8 </em><em>and </em><em>y2 </em><em>is</em><em>-</em><em>1</em><em>6</em>

<em>m=</em><em>-</em><em>1</em><em>6</em><em>+</em><em>8</em><em>/</em><em>-</em><em>1</em><em>7</em><em>+</em><em>1</em><em>2</em>

<em> </em><em> </em><em> </em><em>=</em><em>-</em><em>8</em><em>/</em><em>-</em><em>5</em><em> </em><em>or1.</em><em>6</em>

<em>then</em><em> </em><em>use </em><em>the </em><em>equation</em>

<em>y-y1</em><em>=</em><em>m(</em><em>x-x1</em><em>)</em>

y+8=1.6(x+12)

y+8=1.6x+19.2

y=1.6x+11.2

I hope this helps and sorry if it's wrong

4 0
3 years ago
Find the slope of the line.​
zimovet [89]

Answer:

Rise -5 and Run 2

Slope of -5/2

8 0
3 years ago
-5=9+c/4 <br>please help me with this problem
DIA [1.3K]
Subtract 9 from both sides. Then you have -14=c/4. Multiply the number by 4. You now have -56=c. :)
7 0
3 years ago
A car had a value of $10,000 and depreciates at a rate of 7% a year. What is the cars value after 3 years.​
SOVA2 [1]

Answer:

Step-by-step explanation:

The exponential decay function is

v(t)=a(b)^t where a is the initial value of the car, b is the rate of decay, and t is the time in years. Our rate of decay can also be written as (1 - r) where r is the depreciation in decimal form. Our equation looks like this:

v(t)=10000(1-.07)^t which simplifies to

v(t)=10000(.93)^t Now we can solve our problem for any number of years you'd like. We've been tasked to find the value of the car after 3 years, so:

v(t)=10000(.93)^3 which simplifies a bit to:

v(t)=10000(.804357) so

v(t) = 8043.57

3 0
3 years ago
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