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8090 [49]
4 years ago
5

What can you infer about the size of sugar particles that are dissolved in a mixture of sugar and water?

Chemistry
1 answer:
laiz [17]4 years ago
3 0
You can infer that the size of sugar particles that are dissolved in a mixture of sugar and water are very small since you cannot see the sugar particles. Sugar is an organic compound which is held by covalent bonding. When we dissolve sugar in water, it does not ionizes or dissociates rather it stays as a sugar molecule dissolved in the solvent which is water. These particles are very which is impossible to be seen by the naked eye. Dissolution involves the solute particles and solvent particles interacting and attracting each other forming a solution. Sugar molecules are attracted to water since it is a polar molecule.
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How to find the value of the equilibrium
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6 0
4 years ago
Ethanol is made by fermentation how is ethonall obtained from the fermentation mixture​
grigory [225]

Answer:

<em><u>Fermentation: Single-celled microorganisms called yeast are added to the slurry. Fermentation is the biochemical process that occurs when yeast break down glucose. Yeast gets energy from glucose. As a result, ethanol is produced.</u></em>

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7 0
3 years ago
Please help, I'm so confused!!!!
masha68 [24]

Answer:

\boxed {\boxed {\sf N_2}}

Explanation:

Let's examine this reaction, especially the coefficients.

N_2+3H_2 \rightarrow 2NH_3

First of all, remember that reactants are used to make the product. They are found on the left of the arrow usually. Therefore, N₂ and H₂ are the reactants, while NH₃ is the product. We can automatically eliminate NH₃ from our answer choices, because it is simply not a reactant.

Next, look at the coefficients.

  • N₂ has no coefficient, so a 1 is implied.
  • H₂ has a coefficient of 3.

Therefore, for the reaction to work, there must be 1 mole of N₂ and 3 moles of H₂.

We have 3.2 moles of N₂ and 5.4 moles of H₂.

Divide each amount given by the required amount for completion.

  • 3.2 mol N₂/ 1 mol N₂= 3.2 times
  • 5.4 mol H₂/ 3  mol H₂=1.8 times

Therefore, there is enough nitrogen to complete the reaction 3.2 times, but only enough hydrogen for 1.8 times. If everything is completely reacted, we will run out of hydrogen and have excess <u>nitrogen</u>.

6 0
3 years ago
Choose all the answers that apply.
Naily [24]

All of the above

Explanation:

Science is a methodical way of investigating the world around us in order to find out the truth and facts about them. Technology is the practical aspect of science.

  • The knowledge and understanding of x-rays as part of the electromagnetic radiation made it possible to use the rays to study the internal structures of substances.
  • The discovery of radioactivity has led to the development of nuclear energy that are produced in nuclear reactors.
  • Satellites are built on the principles of science.
  • Robotic machines are based on scientific studies and electricity originated from a good knowledge of the atom.

Learn more:

radioactivity brainly.com/question/10125168

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3 0
4 years ago
At 25 oC the solubility of mercury(II) sulfide is 1.26 x 10-26 mol/L. Calculate the value of Ksp at this temperature. Give your
ycow [4]

<u>Answer:</u> The solubility product of mercury (II) sulfide is 1.6\times 10^{-52}

<u>Explanation:</u>

Solubility product is defined as the product of concentration of ions present in a solution each raised to the power its stoichiometric ratio.

The chemical equation for the ionization of mercury (II) sulfide follows:

HgS(aq.)\rightleftharpoons Hg^{2+}(aq.)+S^{2-}(aq.)  

                      s                  s

The expression of K_{sp} for above equation follows:

K_{sp}=s\times s

We are given:  

s=1.26\times 10^{-26}M

Putting values in above expression, we get:

K_{sp}=(1.26\times 10^{-26})\times (1.26\times 10^{-26})\\\\K_{sp}=1.59\times 10^{-52}

Hence, the solubility product of mercury (II) sulfide is 1.6\times 10^{-52}

7 0
3 years ago
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