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3 years ago

A manufacturing plant has been found guilty of polluting the nearby river. This is _______ pollution.

Chemistry

2 answers:

Len [333]3 years ago

8 0

Answer:B.)

Explanation:

what the other person said

dusya [7]3 years ago

7 0

Answer:

the answer would be C: point source

Explanation:

because it specified the source of the pollution (manufacturing plant)

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What is the atomic number of hydrogen??

Nataly_w [17]

The number is is surely 1

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3 years ago

How do ionic bonds affect the properties of ionic compounds?

seraphim [82]

C) The bonds prevent ions from moving throughout the crystal, so a solid ionic compound is a poor conductor is your answer, however, technically speaking the bonds prevent electrons from moving, since the ions are locked in place and don't want their electrons to go.

3 0

3 years ago

Read 2 more answers

The concentration of HCl can be determined by titration with a primary standard such as Na2CO3 (sodium carbonate). The titration

Masteriza [31]

Answer:

The concentration of HCl is 0.275 M

Explanation:

Step 1: Data given

Mass of Na2CO3 = 0.521 grams

Molar mass of Na2CO3 = 105.99 g/mol

Volume of HCl = 35.7 mL

Step 2: The balanced equation:

2HCl + Na2CO3 → 2NaCl + CO2 + H2O

CO3(2-) + 2H+ ---> H2O + CO2

Step 3: Calculate moles of Na2CO3

Moles Na2CO3 = mass Na2CO3 / Molar mass Na2CO3

Moles Na2CO3 = 0.521 grams / 105.99 g/mol

Moles Na2CO3 = 0.0049 moles

Step 4: Calculate moles of HCl

For 1 mol of Na2CO3 consumed, we need 2 moles of HCl

moles of HCL = 2 * 0.0049 = 0.0098 moles HCl

Step 5: Calculate molarity of HCl

Molarity = number of moles of HCl / Volume (liters)

Molarity = 0.0098 moles / 0.0357 L

Molarity = 0.275 M

The concentration of HCl is 0.275 M

4 0

3 years ago

Read 2 more answers

A solution is created by dissolving 13.0 grams of ammonium chloride in enough water to make 295 mL of solution. How many moles o

Masja [62]

Answer:

(a) Moles of ammonium chloride = 0.243 moles

(b) $Molarity_{ammonium\ chloride}=0.824\ M$

Explanation:

(a) Mass of ammonium chloride = 13.0 g

Molar mass of ammonium chloride = 53.491 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$Moles= \frac{13.0\ g}{53.491\ g/mol}$

Moles of ammonium chloride = 0.243 moles

(b) Moles of ammonium chloride = 0.243 moles

Volume = 295 mL = 0.295 L ( 1 mL = 0.001 L)

$Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}$

$Molarity_{ammonium\ chloride}=\frac{0.243}{0.295}$

$Molarity_{ammonium\ chloride}=0.824\ M$

Volume = ?

Molarity = 0.824 M

$Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}$

$0.824\ M=\frac{0.0500}{Volume}$

Volume = 0.05 / 0.824 L = 0.06068 L = 60.68 mL

6 0

3 years ago

The vapor pressure of pure benzene is 750.0 torr and the vapor pressure of toluene is 300.0 torr at a certain temperature. You m

kow [346]

Answer:

Mole fraction of benzene in pure solution is 0.4472

Explanation:

Vapor pressure of pure benzene= 750 torr

Vapor pressure of pure toulene= 300 torr

Mole fraction of benzene in vapor= 0.669

1/P=Xa/Pa+ Xb/Pb

Where

Xa = mole fraction of A in water

Xb = mole fraction of B in water

P= Total pressure

Pa= total vapor pressure of pure A

Pb = total vapor pressure of pure B

Xa+Xb=1

Let A be benzene and B be toulene

We have Xa=0.669 and Xb= 0.331

1/P= 0.669/750 + 0.331/300

1/P= 0.000892/torr + 0.001103/torr

1/P=0.001995/torr

P= 501.25torr

We have P= Pa+ Pb

Where Pa= XaPa0

And Pb=XbPb0

Where

Xa= mole fraction of A in solution

Xb= mole fraction of B in solution

Now, substitute the data into the formula

501.25torr=Xa750torr + (1- Xa) 300 torr

Xa450torr + 300torr

Xa(450torr)= 201.25torr

Xa= 0.4472

Therefore, mole fraction of benzene in pure solution is 0.4472

7 0

3 years ago