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patriot [66]
3 years ago
5

In a video game for every 6 enemies you defeat, you earned 3 points. If you defeated 48 enemies, how many points would you have

earned?
Mathematics
1 answer:
PSYCHO15rus [73]3 years ago
6 0

Answer:

144

Step-by-step explanation:

Multiply 48 by 3

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(\stackrel{x_1}{5}~,~\stackrel{y_1}{9})~\hfill \stackrel{slope}{m}\implies 2 ~\hfill \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{9}=\stackrel{m}{2}(x-\stackrel{x_1}{5})

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Does the average person live for at least 1,000,000 minutes?
irakobra [83]
Convert to hours, then days, then years
60 minutes per hour
1000000/60=50000/3=16666.7 hours

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6 0
3 years ago
Read 2 more answers
Which is NOT a polynomial?
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3 0
3 years ago
Two different types of tea are sold in your store. If you know 100 cups of tea were sold and one type sold 5 times as much as th
LiRa [457]

The answer can not be found from the given information

Step-by-step explanation:

Two different types of tea are sold in your store

  • You know 100 cups of tea were sold
  • One type sold 5 times as much as the other type

We need to find how much of each type of tea were sold

Assume that the two types are x and y

∵ x represents one type of tea

∵ y represents the other type of tea

∵ 100 cups of tea where sold

- Add x and y, then equate the sum by 100

∴ x + y = 100 ⇒ (1)

∵ x type is 5 times as much as y type

∴ x = 5y ⇒ (2)

Now we have a system of equations to solve it

Substitute x in equation (1) by equation (2)

∴ 5y + y = 100

∴ 6y = 100

- Divide both sides by 6

∴ y = 16.67

<em>But you know number cups must be whole numbers</em>

The number cups can be 102 <em>OR</em> one type is 4 times as much as the other type

If the number of cups is 102, then

85 cups of one type and 17 cups of the other type were sold

If one type is 4 times as much as the other type, then

80 cups of one type and 20 cups of the other type were sold

The answer can not be found from the given information

Learn more:

You can learn more about the system of equations in brainly.com/question/2115716

#LearnwithBrainly

8 0
3 years ago
I need help with this question
Murrr4er [49]

The number of cows is given by

14\cdot 2^{\frac{y}{5}}

So, after k years, the number of cows will be

14\cdot 2^{\frac{y+k}{5}}

We want this number to be twice as much as the original:

14\cdot 2^{\frac{y+k}{5}} = 2(14\cdot 2^{\frac{y}{5}})

First of all, we can cancel 14 from both sides:

2^{\frac{y+k}{5}} = 2\cdot 2^{\frac{y}{5}}

Finally, on the right hand side, we can use the exponent rule

a^b\cdot a^c=a^{b+c}

to get

2^{\frac{y+k}{5}} = 2^{\frac{y}{5}+1}

To solve this equation, we must impose that the two exponents are the same:

\dfrac{y+k}{5} = \dfrac{y}{5}+1 \iff \dfrac{y+k}{5} = \dfrac{y+5}{5}

And clearly this is true if and only if k=5. So, it will take 5 years for the cow heard to double in number.

You can do the exact same steps to find the doubling time for the sheeps.

8 0
3 years ago
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