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Stolb23 [73]
3 years ago
15

Part A List the substances NaCl, Cl2, CH3Cl, and CH3COOH in order of increasing strength of intermolecular attractions. List the

substances , , , and in order of increasing strength of intermolecular attractions. Cl2
Chemistry
1 answer:
Thepotemich [5.8K]3 years ago
7 0

Answer:

Cl₂ < CH₃Cl < CH₃COOH < NaCl

Explanation:

<em>Part A. List the substances NaCl, Cl₂, CH₃Cl, and CH₃COOH in order of increasing strength of intermolecular attractions.</em>

<em />

NaCl. Na⁺ is bonded to Cl⁻ through a ionic bonding. In the crystalline reticle, unit formulas attract each other through ion-ion forces, which are the strongest type of forces.

Acetic acid (CH₃COOH) has H atoms bonded to more electronegative O atoms. This leads to the formation of hydrogen bondings, which constitute an especially strong case of dipole-dipole forces.

Chloromethane (CH₃Cl) is a polar molecule due to the asymmetrical distribution of charge density. The resulting intermolecular attractions are dipole-dipole forces.

Cl₂ is nonpolar and it has the weakest type of intermolecular attractions, dispersion forces.

The order of increasing strength is Cl₂ < CH₃Cl < CH₃COOH < NaCl

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Helppppp pleaseeee xxxxxx
kogti [31]

Answer:

2812.6 g of H₂SO₄

Explanation:

From the question given above, the following data were obtained:

Mole of H₂SO₄ = 28.7 moles

Mass of H₂SO₄ =?

Next, we shall determine the molar mass of H₂SO₄. This can be obtained as follow:

Molar mass of H₂SO₄ = (1×2) + 32 + (16×4)

= 2 + 32 + 64

= 98 g/mol

Finally, we shall determine the mass of H₂SO₄. This can be obtained as follow:

Mole of H₂SO₄ = 28.7 moles

Molar mass of H₂SO₄ =

Mass of H₂SO₄ =?

Mole = mass / Molar mass

28.7 = Mass of H₂SO₄ / 98

Cross multiply

Mass of H₂SO₄ = 28.7 × 98

Mass of H₂SO₄ = 2812.6 g

Thus, 28.7 mole of H₂SO₄ is equivalent to 2812.6 g of H₂SO₄

3 0
3 years ago
What is the number of moles in 546 g strontium nitrite?
Eduardwww [97]
The answer is 2.58 mol
4 0
3 years ago
How many meters do you cover in a 10-kilometer (10-K) race?
attashe74 [19]

Answer:

100

Explanation:

3 0
3 years ago
Read 2 more answers
Unit 1- Unit Assessment (Matter &amp; Density)
konstantin123 [22]

Answer:

<h3>The answer is 11 g/mL</h3>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume} \\

From the question

mass = 3025 g

volume = 275 mL

We have

density =  \frac{3025}{275}  \\

We have the final answer as

<h3>11 g/mL</h3>

Hope this helps you

7 0
3 years ago
What would be the major product obtained from hydroboration–oxidation of the following alkenes?
zmey [24]

Answer:

a. 3-methylbutan-2-ol

b. 2-methylcyclohexan-1-ol

Explanation:

For this reaction, we must remember that the hydroboration is an <u>"anti-Markovnikov" reaction</u>. This means that the "OH" will be added at the <em>least substituted carbon of the double bond.</em>

In the case of <u>2-methyl-2-butene</u>, the double bond is between carbons 2 and 3. Carbon 2 has two bonds with two methyls and carbon 3 is attached to 1 carbon. Therefore <u>the "OH" will be added to carbon three</u> producing <u>3-methylbutan-2-ol</u>.

For 1-methylcyclohexene, the double bond is between carbons 1 and 2. Carbon 1 is attached to two carbons (carbons 6 and 7) and carbon 2 is attached to one carbon (carbon 3). Therefore<u> the "OH" will be added to carbon 2</u> producing <u>2-methylcyclohexan-1-ol</u>.

See figure 1

I hope it helps!

8 0
3 years ago
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