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Softa [21]
3 years ago
14

When aluminum is placed in concentrated hydrochloric acid, hydrogen gas is produced. 2 Al ( s ) + 6 HCl ( aq ) ⟶ 2AlCl3 ( aq ) +

3 H 2 ( g ) What volume of H 2 ( g ) is produced when 8.60 g Al ( s ) reacts at STP
Chemistry
1 answer:
Rufina [12.5K]3 years ago
6 0

Answer:

The answer to your question is  V = 19.9 L

Explanation:

Data

mass of Al = 8.60 g

volume of H₂ = ?

Balanced chemical reaction

                 2Al  +  6HCl  ⇒   2AlCl₃  +  3H₂

1.- Use proportions to calculate the mass of H₂ produced

Atomic mass of Al = 2 x 27 = 54 g

Atomic mass of H₂ = 6 x 1 = 6 g

                54 g of Al -------------------- 6 g of H₂

                  8 g  of Al -------------------  x

                  x = (8 x 6) / 54

                  x = 48 / 54

                  x = 0.89 g of H₂

2.- Calculate the volume of H₂

- Convert the H₂ to moles

                    1 g of H₂ --------------- 1 mol

                   0.89 g    ---------------- x

                    x = 0.89 moles

                    1 mol of H₂ -------------- 22.4 l

                   0.89 moles  ------------- x

                    x = (0.89 x 22.4) / 1

                   x = 19.9 L                        

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Thorium-234 has a half-life of 24.1 days. How many grams of a 150 g sample would you have after 120.5 days?
chubhunter [2.5K]

Answer:

8.625 grams of a 150 g sample of Thorium-234  would be left after 120.5 days

Explanation:

The nuclear half life represents the time taken for the initial amount of sample  to reduce into half of its mass.

We have given that the half life of thorium-234 is 24.1 days. Then it takes 24.1 days for a Thorium-234 sample to reduced to half of its initial amount.

Initial amount of Thorium-234 available as per the question is 150 grams

So now  we start with 150 grams  of Thorium-234

150 \times \frac{1}{2}=24.1

75 \times \frac{1}{2} =48.2

34.5 \times \frac{1}{2} =72.3

17.25 \times \frac{1}{2} =96.4

8.625\times \frac{1}{2} =120.5

So after 120.5 days the amount of sample that remains is 8.625g

In simpler way , we can use the below formula to find the sample left

A=A_{0} \cdot \frac{1}{2^{n}}

Where

A_0  is the initial sample amount  

n = the number of half-lives that pass in a given period of time.

7 0
3 years ago
How much heat is needed to change 5g of ice at 0°C to<br> water at 50°C?
natta225 [31]

Answer:

400cal

Explanation:

Since ice melted at 0 Celesius then the heat gained by ice (latent heat) will melt it so you should substitute in that law

Q=mlf ..where Q is the heat required to convert ice to water , m is the mass of ice and lf is the latent heat of fusion

Q=5∗80=400cal

6 0
3 years ago
Passing an electric current through a sample of water (H2O) can cause the water to decompose into hydrogen gas (H2) and oxygen g
Lerok [7]

The mass of water decomposed to produce 50 g oxygen has been 56.28 g. Thus, option D is correct.

The reaction for the decomposition of water has been:

\rm 2\;H_2O\;\rightarrow\;H_2\;+\;O_2

From the balanced equation, 2 moles of water decomposes to form 1 moles of hydrogen and 1 mole of oxygen.

The mass of oxygen produced has been 50 g. The moles of oxygen has been given by:

\rm Moles=\dfrac{mass}{molar\;mass}

The moles of oxygen has been:

\rm Moles_O_2=\dfrac{50}{32}\;mol\\Moles_O_2=1.5625\;mol

The moles of oxygen produced has been 1.5625 mol.

The moles of hydrogen decomposed has been given from the balanced chemical equation as:

\rm 1 \;mole\;O_2=2\;mole\;H_2O\\1.5625\;mol\;O_2=1.5625\;\times\;2\;mol\;H_2O\\1.5625\;mol\;O_2=3.125\;mol\;H_2O

The moles of hydrogen decomposes has been 3.125 mol.

The mass of hydrogen decomposed has been given by:

\rm Mass=moles\;times\;molar\;mass\\Mass_{H_2O}=3.125\;\times\;18.01\;g\\Mass_{H_2O}=56.28\;g

The mass of water decomposed to produce 50 g oxygen has been 56.28 g. Thus, option D is correct.

For more information about moles produced, refer to the link:

brainly.com/question/10606802

8 0
2 years ago
An ionic bond involves _____.A. an attraction between ions of opposite chargeB. water avoidanceC. the sharing of a single pair o
allochka39001 [22]

Answer: D i think

Explanation: Im sorry if it is wrong lol!! I pretty sure thats the answer...

8 0
3 years ago
9. Carbon-14 has a half-life of 5,730 years. How many years have passed after 3<br> half-lives?
ella [17]

Answer:

120 gram sample of a radioactive element, how many grams of that element will be left after 3 half-lives have passed? If you have a 300

Explanation:

Hope this helps!

7 0
3 years ago
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