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3 years ago

Identify the element with 3 energy levels and 2 valence electrons.

Chemistry

1 answer:

bixtya [17]3 years ago

8 0

Answer:

itz elementary school in new Jersey city and I was in school for a little while I had a phone and a couple days later and I'm going next week and I'm gonna go back and watch Netflix and get some headphones and a lot more like a child and a couple more like this

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Chất nào sau đây là chất điện li mạnh trong H2O

erica [24]

Answer:

những lựa chọn ở đâu?

Explanation:

Hy vọng nó sẽ giúp ích;>

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3 years ago

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In the laboratory you are asked to make a 0.565 m sodium bromide solution using 315 grams of water. How many grams of sodium bro

Scorpion4ik [409]

Answer : The mass of sodium bromide added should be, 18.3 grams.

Explanation :

Molality : It is defined as the number of moles of solute present in kilograms of solvent.

Formula used :

$Molality=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Mass of solvent}}$

Solute is, NaBr and solvent is, water.

Given:

Molality of NaBr = 0.565 mol/kg

Molar mass of NaBr = 103 g/mole

Mass of water = 315 g

Now put all the given values in the above formula, we get:

$0.565mol/kg=\frac{\text{Mass of NaBr}\times 1000}{103g/mole\times 315g}$

$\text{Mass of NaBr}=18.3g$

Thus, the mass of sodium bromide added should be, 18.3 grams.

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3 years ago

How many grams of carbon would be present in carbon monoxide that contains 2.6 grams of oxygen?

Andreas93 [3]

Answer:

1.95g

Explanation:

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2 years ago

PLEASE HELP!! 40 POINTS

PSYCHO15rus [73]

Answer:

1) 6.524779402×10^(-17)

2)521.1g

3)113

Explanation:

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3 years ago

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20.352 mL of chlorine under a pressure of 680. mm Hg are

Lunna [17]

Answer:

0.01144L or 1.144x10^-2L

Explanation:

Data obtained from the question include:

V1 (initial volume) = 20.352 mL

P1 (initial pressure) = 680mmHg

P2 (final pressure) = 1210mmHg

V2 (final volume) =.?

Using the Boyle's law equation P1V1 = P2V2, the volume of the container can be obtained as follow:

P1V1 = P2V2

680 x 20.352 = 1210 x V2

Divide both side by 1210

V2 = (680 x 20.352)/1210

V2 = 11.44mL

Now we need to convert 11.44mL to L in order to obtain the desired result. This is illustrated below:

1000mL = 1 L

11.44mL = 11.44/1000 = 0.01144L

Therefore the volume of the container is 0.01144L or 1.144x10^-2L

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3 years ago

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