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Anettt [7]
3 years ago
10

Gravitational force is a(n)? A) attractive force B) repulsive force C) both an attractive and repulsive force D) neither an attr

active or repulsive force
Physics
1 answer:
aleksley [76]3 years ago
8 0

Answer: In the case of gravity, mediated by spin 2 particles, charge is mass, which is always positive. Thus, q1q2 is always greater than zero, and gravity is always attractive. For spin 0 force mediators, however, there is no restriction on the charges and you can very well have repulsive forces.

Explanation: C) both an attractive and repulsive force is the answer

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Calculate the average net force.
MrRa [10]

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<h2><u>given</u></h2>

<em>mass</em><em> </em><em>=</em><em> </em><em>39</em><em>5</em><em>0</em><em> </em><em>kg</em>

<em>speed</em><em>=</em><em> </em><em>2</em><em>5</em><em>m</em><em>/</em><em> </em><em>sec</em>

<em>time</em><em>=</em><em> </em><em>1</em><em>0</em><em>.</em><em>5</em><em> </em><em>sec</em>

<h2><em>To</em><em> </em><em>find</em><em> </em></h2>

<em>force</em><em> </em>

<h2><em><u>Solution</u></em></h2>

<h3><em>☄️</em><em>Formula</em><em> </em><em>of</em><em> </em><em>force</em><em> </em></h3>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em>

<em>\fbox{f = m.a}</em>

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<em>accler</em><em>ation</em><em>=</em><em> </em><em>change</em><em> </em><em>in</em><em> </em><em>Velocity</em><em>/</em><em>time</em>

<em>accle</em><em>ration</em><em>=</em><em> </em><em>2</em><em>5</em><em>/</em><em>1</em><em>0</em><em>.</em><em>5</em>

<u><em>acc</em><em>leration</em><em>=</em><em> </em><em>2.38</em><em> </em><em>m</em><em>/</em><em>sec²</em></u>

<u><em>put</em><em> </em><em>the</em><em> </em><em>value</em><em> </em><em>of</em><em> </em><em>accle</em><em>ration</em><em> </em><em>in</em><em> </em><em>the </em><em>formula</em><em> of</em><em> force</em></u>

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3 0
3 years ago
A 2.40 kgkg can of coffee moving at 1.50 m/sm/s in the +x+x-direction on a kitchen counter collides head-on with a 1.20 kgkg box
Monica [59]

Answer:

1.35 m/s in the +x direction

Explanation:

Mass of can of coffee, m = 2.4 kg

Initial velocity of can of coffee, u = 1.5 m/s

Mass of box of macaroni, M = 1.2 kg

Initial velocity of box of macaroni, U = 0 m/s

Final velocity of can of coffee, v = 0.825 m/s

We can find the final velocity of the box of macaroni, V, by using the Principle of Conservation of momentum:

Total initial momentum = Total final momentum

Momentum is given as the product of mass and velocity. Hence:

mu + MU = mv + MV

(2.4 * 1.5) + (1.2 * 0) = (2.4 * 0.825) + (1.2 * V)

3.6 + 0 = 1.98 + 1.2V

1.2V = 3.6 - 1.98 = 1.62

=> V = 1.62/1.2

V = 1.35 m/s

The final velocity of the box of macaroni is 1.35 m/s and it is in the +x direction.

3 0
3 years ago
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