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JulijaS [17]
2 years ago
13

A climber using bottled oxygen accidentally drops the oxygen bottle from an altitude of 4500 m. If the bottle fell straight down

this entire distance, what is the velocity of the 3-kg bottle just prior to impact at sea level?A. 300 m/s.B. 150 m/s.C. 30 m/s.D. 3 m/s.
Physics
1 answer:
Trava [24]2 years ago
3 0

Answer:

v= 300 m/s

Explanation:

Given that

altitude ,h= 4500 m

The mass ,m = 3 kg

Lets take acceleration due to gravity , g= 10 m/s²

The speed before impact at sea  level =  v

Initial speed ,u = 0 m/s

We know that

v²=u²+2 g h

v=final speed

u=initial speed

h=height

Now by putting the values in the above equation

v² = 0²+ 2 x 10 x 4500

v²=90000

v= 300 m/s

Therefore the speed at sea level will be 300 m/s.

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The range of frequencies  of visible light in a vacuum is mathematically given as

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<h3>What is the range of frequencies of visible light in a vacuum?</h3>

Question Parameters:

The wavelengths of visible light vary from about 300 nm to 700 nm.

Generally, the equation for the frequency   is mathematically given as

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Fmax=1*10^15Hz

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A person tries to lift each object with a force of 25 N, upward. Which
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Answer:

Option C. Objects 1 and 3 will not move, and objects 2 and 4 will accelerate

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Explanation:

The following data were obtained from the question:

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1 >>>>>>>>>>>>>>>> 35

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For object 3:

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Force applied = 25 N

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For object 4:

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