Question

A capacitor consists of two closely spaced metal conductors of large area, separated by a thin insulating foil. it has an electrical capacity of 3000.0 μf and is charged to a potential difference of 87.0 v. calculate the amount of energy stored in the capacitor.

Answer 1

The energy stored in a capacitor is given by:

$U=\frac{1}{2}CV^2$

where C is the capacitance and V is the potential difference applied across the capacitor.

In this problem, we have:

$C=3000 \mu F= 3000 \cdot 10^{-6} F$

$V=87.0 V$

Substituting the numbers into the equation, we find the energy stored:

$U=\frac{1}{2}(3000 \cdot 10^{-6} F)(87 V)^2=11.4 J$