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kompoz [17]
3 years ago
9

Which of the following expressions could be used to find the sale price of an item that costs d dollars if it is on sale for 30%

off? 30 d 0.3 d 0.7 d 70 d
Mathematics
1 answer:
Elenna [48]3 years ago
6 0

Greetings!

An item at full price is 100%, or by using the percentage formula: (\frac{percentage}{100})

If something is at 30% off, that means it is 70% of the original price (because minus the percentage from the 100%)

So by substituting the numbers into the percentage formula you end up with:

(\frac{70}{100}) which is 0.7

So your answer would be D, 0.7!


Hope this helps!

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the set points (-4,1),(-4,-4),(2,-4),(2,1) identifies the vertices of a quadrilateral which is the most specific description of
raketka [301]

Answer:

The answer is a trapezoid.

Hope this helped!


6 0
3 years ago
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Solve for p. <br> −160=22+8(3p−4)
Aneli [31]
-160=22+8(3p-4)
Use distributive property
-160=22+24p-32
-160=24p-10
Add 10 for both side
-160+10=24p-10+10
-150=24p
Divided 24 for both side
-150/24=24p/24
p=-6.25
Check:
-160=22+8(3p+4)
-160=22+8[3(-6.25)-4]
-160=22+8(-18.75-4)
-160=22+8(-22.75)
-160=22-182
-160=-160. As a result, x=-6.25. Hope it help!
3 0
3 years ago
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What two consecutive even integers have a sum of -66?
pshichka [43]

Answer:

the sum of 2 consecutive even integers is 66.

Step-by-step explanation:

This means that if one integers is x, the other must be either x-2 or x+2. Therefore, we can write 6=x+(×-2)=2×2. Solving for x, we can find ×=34. this means that the other integer is 34-2=32. indeed, 32+34=66, and done hope this helped C:

7 0
3 years ago
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D/d{cosec^-1(1+x²/2x)} is equal to​
SIZIF [17.4K]

Step-by-step explanation:

\large\underline{\sf{Solution-}}

\rm :\longmapsto\:\dfrac{d}{dx} {cosec}^{ - 1} \bigg( \dfrac{1 +  {x}^{2} }{2x} \bigg)

Let assume that

\rm :\longmapsto\:y =  {cosec}^{ - 1} \bigg( \dfrac{1 +  {x}^{2} }{2x} \bigg)

We know,

\boxed{\tt{  {cosec}^{ - 1}x =  {sin}^{ - 1}\bigg( \dfrac{1}{x} \bigg)}}

So, using this, we get

\rm :\longmapsto\:y = sin^{ - 1} \bigg( \dfrac{2x}{1 +  {x}^{2} } \bigg)

Now, we use Method of Substitution, So we substitute

\red{\rm :\longmapsto\:x = tanz \: \rm\implies \:z =  {tan}^{ - 1}x}

So, above expression can be rewritten as

\rm :\longmapsto\:y = sin^{ - 1} \bigg( \dfrac{2tanz}{1 +  {tan}^{2} z} \bigg)

\rm :\longmapsto\:y = sin^{ - 1} \bigg( sin2z \bigg)

\rm\implies \:y = 2z

\bf\implies \:y = 2 {tan}^{ - 1}x

So,

\bf\implies \: {cosec}^{ - 1}\bigg( \dfrac{1 +  {x}^{2} }{2x} \bigg) = 2 {tan}^{ - 1}x

Thus,

\rm :\longmapsto\:\dfrac{d}{dx} {cosec}^{ - 1} \bigg( \dfrac{1 +  {x}^{2} }{2x} \bigg)

\rm \:  =  \: \dfrac{d}{dx}(2 {tan}^{ - 1}x)

\rm \:  =  \: 2 \: \dfrac{d}{dx}( {tan}^{ - 1}x)

\rm \:  =  \: 2 \times \dfrac{1}{1 +  {x}^{2} }

\rm \:  =  \: \dfrac{2}{1 +  {x}^{2} }

<u>Hence, </u>

\purple{\rm :\longmapsto\:\boxed{\tt{ \dfrac{d}{dx} {cosec}^{ - 1} \bigg( \dfrac{1 +  {x}^{2} }{2x} \bigg) =  \frac{2}{1 +  {x}^{2} }}}}

<u>Hence, Option (d) is </u><u>correct.</u>

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