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klemol [59]
4 years ago
7

Match the correct term with each part of the wave

Physics
1 answer:
Misha Larkins [42]4 years ago
6 0
6 . . . . . a crest
7 . . . . . the amplitude
8 . . . . . the wavelength
9 . . . . . a trough
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Xander was traveling at a final velocity of 4.5 m/s for 3.5 seconds. Finley was traveling at a final velocity of 3.6 m/s for 4.2
Dima020 [189]

the answer is Finley, Xander, Max

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3 years ago
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Les changements d'état de la matière
ale4655 [162]

Answer:

Les changements d'état sont des changements physiques. Ils se produisent lorsque la matière absorbe ou perd de l'énergie. Les processus dans lesquels la matière change entre les états liquide et solide sont la congélation et la fusion. Les processus dans lesquels la matière change entre les états liquide et gazeux sont la vaporisation, l'évaporation et la condensation.

Im not french and I used translate so if it messes up with the translation, I am sorry

5 0
3 years ago
A sample contains radioactive atoms of two types, A and B. Initially there are five times as many A atoms as there are B atoms.
victus00 [196]

Answer:

Explanation:

Initially no of atoms of A = N₀(A)

Initially no of atoms of B = N₀(B)

5 X N₀(A)  = N₀(B)

N = N₀ e^{-\lambda t}

N is no of atoms after time t , λ is decay constant and t is time .

For A

N(A) = N(A)₀ e^{-\lambda_1 t}

For B

N(B) = N(B)₀ e^{-\lambda_2 t}

N(A) = N(B) , for t = 2 h

N(A)₀ e^{-\lambda_1 t} = N(B)₀ e^{-\lambda_2 t}

N(A)₀ e^{-\lambda_1 t} = 5 x N₀(A)  e^{-\lambda_2 t}

e^{-\lambda_1 t} = 5  e^{-\lambda_2 t}

e^{\lambda_2 t} = 5  e^{\lambda_1 t}

half life = .693 / λ

For A

.77 =  .693 / λ₁

λ₁ = .9 h⁻¹

e^{\lambda_2 t} = 5  e^{\lambda_1 t}

Putting t = 2 h , λ₁ = .9 h⁻¹

e^{\lambda_2\times  2} = 5  e^{.9\times  2}

e^{\lambda_2\times  2} = 30.25

2 x λ₂ = 3.41

λ₂ = 1.7047

Half life of B = .693 / 1.7047

= .4065 hours .

= .41 hours .

6 0
3 years ago
Consider a metal bar of initial length L and cross-sectional area A. The Young's modulus of the material of the bar is Y. Find t
RUDIKE [14]

Answer:

Spring constant = YA / L

Explanation:

Let F be the force being applied on cross sectional area A of metal bar due to which an extension of ΔL is obtained in the wire of length L then

stress = F / A

strain = ΔL /L

Young's modulus = ( F / A ) / (ΔL /L)

Y = ( F L / A ΔL )

( F / ΔL ) = ( YA / L )

Spring constant = ( F / ΔL )

Spring constant = YA / L

6 0
3 years ago
Light waves are traveling through glass. If the wavelength of some part of the light wave is 4 x 10^(-7) m and the frequency of
Ivenika [448]
Wave speed = fλ
=(5 x 10^14)(4 x 10^-7)
=2 x 10^8

Where f is the frequency and λ is the wavelength
3 0
3 years ago
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