A machine applies a force of 100 newtons over a distance of 10 meters to raise a 500 newton
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A) diagram is shown on the image below
b) Mass m = 450/9.8 = 45.918 KgNet upward force = T + T = 2T = 620 NNet downward force = 290 + 160 = 450 NResultant force F = Net upward force - Net downward force ma = 620 - 450 45.918 a = 170 Acceleration a = 170/45.918 = 3.7 m/s^2 (upward)Here Net upward force > Net downward force, So the resultant force directed upwards, hence acceleration will be upward.
(c)Consider the case of boy alone, then from Newtons law of motion we can write Net force F = n + T - 290 ma = n + 310 - 290 where m = 290/9.8 = 29.59 Kg 29.59 * 3.7 = n + 20 109.483 = n + 20 n = 89.483 N
b) Mass m = 450/9.8 = 45.918 KgNet upward force = T + T = 2T = 620 NNet downward force = 290 + 160 = 450 NResultant force F = Net upward force - Net downward force ma = 620 - 450 45.918 a = 170 Acceleration a = 170/45.918 = 3.7 m/s^2 (upward)Here Net upward force > Net downward force, So the resultant force directed upwards, hence acceleration will be upward.
(c)Consider the case of boy alone, then from Newtons law of motion we can write Net force F = n + T - 290 ma = n + 310 - 290 where m = 290/9.8 = 29.59 Kg 29.59 * 3.7 = n + 20 109.483 = n + 20 n = 89.483 N