Answer:
The acceleration of the sprinter is 1.4 m/s²
Explanation:
Hi there!
The equation of position of the sprinter is the following:
x = x0 + v0 · t + 1/2 · a · t²
Where:
x = position of the sprinter at a time t.
x0 = initial position.
v0 = initial velocity.
t = time.
a = acceleration.
Since the origin of the frame of reference is located at the starting point and the sprinter starts from rest, then, x0 and v0 are equal to zero:
x = 1/2 · a · t²
At t = 9.9 s, x = 71 m
71 m = 1/2 · a · (9.9 s)²
2 · 71 m / (9.9 s)² = a
a = 1.4 m/s²
The acceleration of the sprinter is 1.4 m/s²
Answer:
you could talk about the people and say something like change
Explanation:
Explanation:
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If you tell me the meaning of it, I'll tell you my answer too(ㆁωㆁ)
Answer:
x = 0 m
y = 1.02 m
Explanation:
M1 = 2.09 kg
y1 = 2.97 m
M2 = 2.93 kg
y2 = 2.53 m
M3 = 2.57 kg
y3 = 0 m
M4 = 3.92 kg
y5 = -0.496 m
since all objects are situated on the Y-axis, this means the x coordinate of the center of mass is 0.
To find the y coordinate of the center of mass, we apply the equation below.
sum of moment of the objects about the origin = moment of the total mass of objects about the center of mass
M1.y1 + M2.y2 + M3.y3 + M4.y4 = Mt.Y
(2.09 x 2.97) + (2.93 x 2.53) + (2.57 x 0) + (3.92 x -0.496) = (2.09 + 2.93 + 2.57 + 3.92) Y
11.68 = 11.51 Y
Y = 11.68 / 11.51 = 1.02 m
Answer:
Explanation:
Remark
In general, these 3rd class levers are very inefficient. Because the force distance is smaller than the load distance, you need to pull upward with more force that the weight of the load. So whatever the load is, the force is going to be much greater.
The distances are always measured to the pivot unless you are asked something specific otherwise.
Givens
F = ?
weight = 6N
Force Distance = F*d = 0.5 m
Weight Distance =W*d1 = 2 m
Formula
F*Fd = W*Wd
Solution
F*0.5 = 6 * 2 Divide by 0.5
F = 12/0.5
F = 24 N upwards
