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3 years ago

An object is placed 1.0 cm from a convex mirror with a focal length of 4.0 cm.

Physics

1 answer:

Drupady [299]3 years ago

6 0

Answer:

image distanc=-0.8cm

Explanation:

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Question: A net force of 16 N [40° W of N] is caused by two applied forces acting on the same object. These two forces are: A) 1

Kaylis [27]

The answer is C.......

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4 years ago

How long does the president serve a term in office

Ilya [14]

Answer:

United States Electoral College to a four-year term, with a term limit of two terms (totaling eight years) or a maximum of ten years if the president acted as president for two years or less in a term

Explanation:

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3 years ago

Read 2 more answers

What is the momentum of an object with a mass of 60 kg and velocity of 10 m/s?<br><br> heeelp

Pavlova-9 [17]

Answer:

Linear momentum= Mass*Velocity

P=mv

P=60*10

P=600Kg m/s

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3 years ago

A lunar eclipse occurs only when the Moon is new. A lunar eclipse occurs only when the Moon is new. True False

Fittoniya [83]

False. False.

A lunar eclipse occurs only when the moon is full.

A solar eclipse occurs only when the moon is new.

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4 years ago

The tub of a washer goes into its spin-dry cy-cle, starting from rest and reaching an angularspeed of 3.1 rev/s in 10.7 s.At thi

neonofarm [45]

Answer:

35 revolutions

Explanation:

t = Time taken

$\omega_f$ = Final angular velocity

$\omega_i$ = Initial angular velocity

$\alpha$ = Angular acceleration

$\theta$ = Number of rotation

Equation of rotational motion

$\omega_f=\omega_i+\alpha t\\\Rightarrow \alpha=\frac{\omega_f-\omega_i}{t}\\\Rightarrow \alpha=\frac{3-0}{10.7}\\\Rightarrow \alpha=0.28037\ rev/s^2$

$\omega_f^2-\omega_i^2=2\alpha \theta\\\Rightarrow \theta=\frac{\omega_f^2-\omega_i^2}{2\alpha}\\\Rightarrow \theta=\frac{3.1^2-0^2}{2\times 0.28037}\\\Rightarrow \theta=17.13806\ rev$

Number of revolutions in the 10.7 seconds is 17.13806

$\omega_f=\omega_i+\alpha t\\\Rightarrow \alpha=\frac{\omega_f-\omega_i}{t}\\\Rightarrow \alpha=\frac{0-3.1}{11.2}\\\Rightarrow a=-0.27678\ rev/s^2$

$\omega_f^2-\omega_i^2=2\alpha \theta\\\Rightarrow \theta=\frac{\omega_f^2-\omega_i^2}{2\alpha}\\\Rightarrow \theta=\frac{0^2-3.1^2}{2\times -0.27678}\\\Rightarrow \theta=17.36035\ rev$

Number of revolutions in the 11.2 seconds is 17.36035

Total total number of revolutions in the 21.9 second interval is 17.13806+17.36035 = 34.49841 = 35 revolutions

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4 years ago