3 years ago

A car moving at a velocity of 25m/s, so how much distance it will travel in 5 seconds?

Physics

1 answer:

denpristay [2]3 years ago

3 0

Answer:

125 meters

Explanation:

5s= s*5 so 25*5=125 m

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A 6157 N piano is to be pushed up a(n) 2.41 m frictionless plank that makes an angle of 21.9 ◦ with the horizontal. Calculate th

xz_007 [3.2K]

Answer:

Work done, W = 5534.53 J

Explanation:

It is given that,

Force acting on the piano, F = 6157 N

It is pushed up a distance of 2.41 m friction less plank.

Let W is the work done in sliding the piano up the plank at a slow constant rate. It is given by :

$W=Fd\ sin\theta$

Since, $F=F\ sin\theta$ (in vertical direction)

$W=6157\times 2.41\ sin(21.9)$

W = 5534.53 J

So, the work done in sliding the piano up the plank is 5534.53 J. Hence, this is the required solution.

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3 years ago

A bicyclist of mass 60kg supplies 340W of power while riding into a 5 m/s head wind. The frontal area of the cyclist and bicycle

NikAS [45]

Answer:

87.1 mph

Explanation:

We are given that

Mass,m=60 kg

Power,P=340 W

Speed,v=5 m/s

Area, $A=0.344 m^2$

Drag coefficient, $C_d=0.88$

Coefficient of rolling resistance, $\mu_r=0.007$

Friction force, $f=\mu_rmg=0.007\times 60\times 9.8=4.1 N$

Where $g=9.8 m/s^2$

Let speed of cyclist=v'

Drag force, $F_d=\frac{1}{2}\rho_{air}AC_dv^2$

Density of air, $\rho_{air}=1.225 kg/m^3$

$F_d=\frac{1}{2}\times 1.225\times 0.344\times 0.88(5)^2=4.635N$

Power,P= $(F_d+f)\times v'$

$340=(4.1+4.635) v'=8.735v'$

$v'=\frac{340}{8.735}=38.9m/s$

$v'=87.1 mph$

1 m=0.00062137 miles

1 hour=3600 s

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3 years ago

a student pushes on a crate with a force of 100 N directed to the right. what force does the crate exert on a student

soldi70 [24.7K]

100N to the left. Newton's 3rd law action and reaction

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2 years ago

Which change will cause an increase in the electric current produced through electromagnetic induction?using more wire loops in

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<span>using more wire loops in the solenoid</span>

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3 years ago

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Answer: Not 100% sure but I think it’s C.

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