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I am Lyosha [343]
3 years ago
10

A particle performing uniform circular motion has angular momentum L. What will be the new angular momentum, if its angular freq

uency is doubled and its kinetic energy is halved.
Physics
1 answer:
GaryK [48]3 years ago
3 0

Answer:

Angular Momentum

Explanation:

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A large crate with mass m rests on a horizontal floor. The static and kinetic coefficients of friction between the crate and the
Mariana [72]

a) F=\frac{\mu_k mg}{cos \theta - \mu_k sin \theta}

Here the crate is moving at constant velocity, so no acceleration:

a = 0

Let's analyze the forces acting along the horizontal and vertical direction.

- Vertical direction: the equation of the forces is

R-Fsin \theta - mg = 0 (1)

where

R is the normal reaction of the floor (upward)

F sin \theta is the component of the force F in the vertical direction (downward)

mg is the weight of the crate (downward)

- Horizontal direction: the equation of the forces is

F cos \theta - \mu_k R = 0 (2)

where

F cos \theta is the horizontal component of the force F (forward)

\mu_k R is the force of friction (backward)

From (1) we get

R=Fsin \theta +mg

And substituting into (2)

F cos \theta - \mu_k (Fsin \theta +mg) = 0\\F cos \theta -\mu _k F sin \theta = \mu_k mg\\F(cos \theta - \mu_k sin \theta) = \mu_k mg\\F=\frac{\mu_k mg}{cos \theta - \mu_k sin \theta}

b) \mu_s=cot(\theta)

In this second case, the crate is still at rest, so we have to consider the static force of friction, not the kinetic one.

The equations of the forces will be:

R-Fsin \theta - mg = 0 (1)

F cos \theta - \mu_s R = 0 (2)

In this second case, we want to find the critical value of \mu_s such that the woman cannot start the crate: this means that the force of friction must be at least equal to the component of the force pushing on the horizontal direction, F cos \theta.

Therefore, using the same procedure as before,

R=Fsin \theta +mg

F cos \theta - \mu_s (Fsin \theta +mg) = 0

And solving for \mu_s,

F cos \theta = \mu_s (Fsin \theta +mg) \\\mu_s = \frac{F cos \theta}{F sin \theta + mg}

Now we analyze the expression that we found. We notice that if the force applied F is very large, F sin \theta >> mg, therefore we can rewrite the expression as

\mu_s \sim \frac{F cos \theta}{F sin \theta}\\\mu_s=cot(\theta)

So, this is the critical value of the coefficient of static friction.

8 0
3 years ago
Which of the following are disadvantages of solar energy? Check all that apply. A. It contributes to global warming. B. It is ex
guajiro [1.7K]
B, C, and D.

Solar energy is green energy, it wouldn't contribute to global warming. However some places of the world don't receive as much sunlight (the poles) and at night you don't receive as much sunlight either. Solar energy is also very expensive to farm.
8 0
3 years ago
What is the relationship between power and voltage?
kipiarov [429]

<u>Answer:</u>

The power and voltage are related through Power Rule .

<u> Explanation : </u>

Power Rule  states  that the current I  that flows the element in the circuit  with a loss in voltage V,  then the amount of  power dissipated by that element in the circuit is the   multiplicative product of  voltage and the current.

Mathematically, power law  is

\boldsymbol{P}=\boldsymbol{I} \times \boldsymbol{V}

The rate of work done or the rate of energy consumption or production is  termed as power.Unit of power is denoted as W(watts).

Potential energy between  any two points on a circuit is called as  Voltage and is measured in volts (V) .

3 0
3 years ago
When two sticks are laid end-to-end they cover a length of 8.32 feet. One stick is 2.93 ft longer than the other. What is the le
77julia77 [94]

To solve this problem we will start by defining the length of the shortest stick as 'x'. And the magnitude of the longest stick, according to the statement as

x+2.93

Both cover a magnitude of 8.32 ft, therefore

x +(x+2.97) = 8.32

Now solving for x we have,

x + (x + 2.93) = 8.32

2x + 2.93 = 8.32

2x = 8.32 - 2.93

x = \frac{ 8.32 - 2.93}{2}

x = 2.695 ft

Therefore the shorter stick is 2.695ft long.

7 0
4 years ago
PLEASE HELP ASAP!!! NO LINKS! Which type of wave does the illustration depict?
Xelga [282]

Answer:

Transverse wave

Explanation:

The wave is moving forwards from the hand to the point of attachment

3 0
3 years ago
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