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4 years ago

Two weight lifters (Herb and Foley) wonder which one is doing the most work. Which statement is true?

Physics

2 answers:

Lostsunrise [7]4 years ago

8 0

Answer:

The answer would be B.

Explanation:

Luda [366]4 years ago

3 0

The solution would be like this for this specific problem:

Work = 50kg * 1.5m

= 75

Work = 55kg * 1 m

=55

75 > 55

Therefore, the statement that is true is “Herb lifting 50 kg 1.5 meters does more work than Foley lifting 55 kg 1 meter.”

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3 years ago

A boy pushes a cart with a constant velocity of 0.5m/s by applying a force of 60 N. What is the total frictional force acting on

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Answer:

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Explanation:

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4 years ago

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3 years ago

Read 2 more answers

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3 years ago

A 77.0−kg short-track ice skater is racing at a speed of 12.6 m/s when he falls down and slides across the ice into a padded wal

sukhopar [10]

Answer:

-6112.26 J

Explanation:

The initial kinetic energy, $KE_i$ is given by

$KE_i=0.5mv_1^{2$ } where m is the mass of a body and $v_i$ is the initial velocity

The final kinetic energy, $KE_f$ is given by

$KE_f=0.5mv_f^{2}$ where $v_f$ is the final velocity

Change in kinetic energy, $\triangle KE$ is given by

$\triangle KE=KE_f-KE_i=0.5mv_f^{2}-0.5mv_1^{2}=0.5m(v_f^{2}-v_i^{2})$

Since the skater finally comes to rest, the final velocity is zero. Substituting 0 for $v_f$ and 12.6 m/s for $v_i$ and 77 Kg for m we obtain

$\triangle KE=0.5*77*0^{2}-0.5*77*(0^{2}-12.6^{2})=-6112.26 J$

From work energy theorem, work done by a force is equal to the change in kinetic energy hence for this case work done equals -6112.26 J

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3 years ago