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3 years ago

Two weight lifters (Herb and Foley) wonder which one is doing the most work. Which statement is true?

Physics

2 answers:

Lostsunrise [7]3 years ago

8 0

Answer:

The answer would be B.

Explanation:

Luda [366]3 years ago

3 0

The solution would be like this for this specific problem:

Work = 50kg * 1.5m

= 75

Work = 55kg * 1 m

=55

75 > 55

Therefore, the statement that is true is “Herb lifting 50 kg 1.5 meters does more work than Foley lifting 55 kg 1 meter.”

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Most automobiles have a coolant reservoir to catch radiator fluid that may overflow when the engine is hot. A radiator is made o

Colt1911 [192]

Answer:

There is a loss of fluid in the container of 0.475L

Explanation:

To solve the problem it is necessary to take into account the concepts related to the change of voumen in a substance depending on the temperature.

The formula that describes this thermal expansion process is given by:

$\Delta V = \beta V_0 \Delta T$

Where,

$\Delta V =$ Change in volume

$V_0 =$ Initial Volume

$\Delta T =$ Change in temperature

$\beta =$ coefficient of volume expansion (Coefficient of copper and of the liquid for this case)

There are two types of materials in the container, liquid and copper, so we have to change the amount of Total Volume that would be subject to,

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Where,

$\Delta V_l$ = Change in the volume of liquid

$\Delta V_c$ = Change in the volume of copper

Then replacing with the previous equation we have:

$\Delta V = \beta_l V_0 \Delta T- \beta_c V_0 \Delta T$

$\Delta V = (\beta_l-\beta_c)V_0\Delta T$

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$\beta_c = 51*10^{-6}/\°C$

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Replacing we have that,

$\Delta V = (\beta_l-\beta_c)V_0\Delta T$

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3 years ago

You are exploring a distant planet. When your spaceship is in a circular orbit at a distance of 630 km above the planet's surfac

Anarel [89]

Answer:

$R = 24.3 m$

Explanation:

As we know that the orbital speed is given as

$v = \sqrt{\frac{GM}{R + h}}$

here we know that

v = 5500 m/s

$R = 4.48 \times 10^6 m$

$h = 630 km$

now we have

$5500 = \sqrt{\frac{(6.6 \times 10^{-11})M}{4.48 \times 10^6 + 6.30\times 10^5}}$

$M = 2.34 \times 10^24 kg$

now acceleration due to gravity of planet is given as

$a = \frac{GM}{R^2}$

$a = \frac{(6.6 \times 10^{-11})(2.34 \times 10^{24})}{(4.48\times 10^6)^2}$

$a = 7.7 m/s^2$

now range of the projectile on the surface of planet is given as

$R = \frac{v^2 sin2\theta}{g}$

$R = \frac{14.6^2 sin(2\times 30.8)}{7.7}$

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3 years ago

Autotrophic plants do not require which of the following? solar energy carbon dioxide water oxygen NextReset

alukav5142 [94]

<span>Autotrophic plants do not require "Oxygen" as it is a waste product of the process of photosynthesis which they do.

In short, Your Final Answer would be Option D

Hope this helps!</span>

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