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N76 [4]
3 years ago
7

2. What is the standard value of acceleration due to gravity or "g"?

Physics
2 answers:
lawyer [7]3 years ago
8 0

Answer:

9.80665 m/s^2

Explanation:

This is the value on Earth.

svp [43]3 years ago
6 0

Answer:

The standard acceleration due to gravity (or standard acceleration of free fall), sometimes abbreviated as standard gravity, usually denoted by ɡ0 or ɡn, is the nominal gravitational acceleration of an object in a vacuum near the surface of the Earth. It is defined by standard as 9.80665 m/s2 (about 32.17405 ft/s2).

Explanation:

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Imagine you’re an engineer making a string of battery powered holiday lights. If a bulb burns out current cannot flow through th
Anit [1.1K]

Answer:

The 2 light bulbs can be connected in parallel to each other to avoid disconnection when one bulb burns out.

Explanation:

The parallel connection is required not series. A parallel connection is the connection of electronic components (e.g bulbs, LED, resistors, capacitors etc) in such a way that the same voltage is supplied across the ends of the components.  While in a series connection, the components are connected to each other end-to-end.

As regard the question, parallel connection ensures that the brightness any of the bulbs is not affected with respect to the other bulbs. And other bulbs continue to function when any burns out. The 2 light bulbs should be connected in parallel to the baterry to avoid disconnection of all the bulbs.

4 0
3 years ago
State Schrodinger equation.​
Elenna [48]

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3 0
2 years ago
You and your friend are pushes hard against a stationary wall. If you push 3 times harder than your friend, then the amount of w
shtirl [24]

Answer:

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5 0
2 years ago
How do you do this question?
umka2103 [35]

Explanation:

The moment of inertia of each disk is:

Idisk = 1/2 MR²

Using parallel axis theorem, the moment of inertia of each rod is:

Irod = 1/2 mr² + m (R − r)²

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I = 2Idisk + 5Irod

I = 2 (1/2 MR²) + 5 [1/2 mr² + m (R − r)²]

I = MR² + 5/2 mr² + 5m (R − r)²

Plugging in values:

I = (125 g) (5 cm)² + 5/2 (250 g) (1 cm)² + 5 (250 g) (5 cm − 1 cm)²

I = 23,750 g cm²

7 0
3 years ago
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