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inessss [21]
3 years ago
11

General form of the equation of a circle with its center at (-2, 1) and passing through (-4, 1)

Mathematics
1 answer:
jonny [76]3 years ago
6 0

 

hello :<span>
<span>an equation of the circle Center at the A(a,b) and ridus : r is :
(x-a)² +(y-b)² = r²
in this exercice : a = -2 and b = 1 (Center at the A(-2,1))
r = AP......P( -4 , 1)
r² = (AP)²
r² = (4+2)² +(1-1)² = 36
an equation of the circle that satisfies the stated conditions.
Center at </span></span> A(-2,1), passing through P(-4, 1) is : (x+2)² +(y-1)² = 36

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2
Snezhnost [94]

An additive inverse of a number (x) is a number which when added to x results in being 0.

The given problem is -3 - (-6)

The additive inverse of -6 is 6

-3 -(-6) = -3 + 6 = 3

Communities property: 6-3 = 3

The answer is:

Because -3+6 is an equivalent expression, the answer is 3

7 0
3 years ago
A mixed number greater than 8.45? my answers are
zalisa [80]
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8 0
3 years ago
Read 2 more answers
5.8 cm converted into cm
agasfer [191]

Answer:

but it is already in cm

5.8 cm is 5.8 cm   but if you want mm

5.8 cm is 58 mm

Step-by-step explanation:

8 0
3 years ago
the point slope form of the equation of a line that passes through (8,4) and (0,2) is y-4=1/4(×-8) what is the slope intercept f
marissa [1.9K]

Answer:

\large\boxed{y=\dfrac{1}{4}x+2}

Step-by-step explanation:

The slope-intercept form of the equation of a line:

y=mx+b

m - slope

b - y-intercept → (0, b)

The point-slope form of the equation of a line:

y-y_1=m(x-x_1)

m - slope

(x₁, y₁) - point

We have the equation of a line:

y-4=\dfrac{1}{4}(x-8)\to m=\dfrac{1}{4}

and the point (0, 2) → b = 2.

Substitute:

y=\dfrac{1}{4}x+2

7 0
3 years ago
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bearhunter [10]
6/12 or 1/2
normal-first one
simplify-second one
hope it helps :)
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