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inessss [21]
3 years ago
11

General form of the equation of a circle with its center at (-2, 1) and passing through (-4, 1)

Mathematics
1 answer:
jonny [76]3 years ago
6 0

 

hello :<span>
<span>an equation of the circle Center at the A(a,b) and ridus : r is :
(x-a)² +(y-b)² = r²
in this exercice : a = -2 and b = 1 (Center at the A(-2,1))
r = AP......P( -4 , 1)
r² = (AP)²
r² = (4+2)² +(1-1)² = 36
an equation of the circle that satisfies the stated conditions.
Center at </span></span> A(-2,1), passing through P(-4, 1) is : (x+2)² +(y-1)² = 36

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Answer:

The 2nd option is correct.

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Step-by-step explanation:

From the graph,

Taking two points

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  • (3, 9)

Finding the rate of change or slope between (0, 0) and (3, 9)

Using the formula

Rate of change = Slope = m =  [y₂ - y₁] /  [x₂ - x₁]

               =  [9 - 0] / [3 - 0]

               = 9 / 1  

               = 3

Thus, the rate of change or slope of the line = m = 3

The slope-intercept form of the line equation

y = mx+b

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Comparing with the slope-intercept form of the line equation y = mx+b

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Hence, the 2nd option is correct.

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