Given :-
- y varies directly as x, and y=14 when x=4.
To Find :-
- the value of y when x=9 .
Solution :-
<u>A</u><u>c</u><u>c</u><u>o</u><u>r</u><u>d</u><u>i</u><u>n</u><u>g</u><u> </u><u>t</u><u>o</u><u> </u><u>Q</u><u>u</u><u>e</u><u>s</u><u>t</u><u>i</u><u>o</u><u>n</u><u> </u><u>,</u>
<u>When</u><u> </u><u>y</u><u> </u><u>=</u><u> </u><u>1</u><u>4</u><u> </u><u>a</u><u>n</u><u>d</u><u> </u><u>x</u><u> </u><u>=</u><u> </u><u>4</u><u> </u><u>,</u>
<u>W</u><u>h</u><u>e</u><u>n</u><u> </u><u>x</u><u> </u><u>=</u><u> </u><u>9</u><u> </u><u>,</u>
- y = 7/2*9
- y = 63/2
- y = 31.5
Answer:
1350.61
Step-by-step explanation:
f(x)=1200(1.03^x)
Answer:
24.23
Step-by-step explanation:
The tan(x) would equal to the opposite side over the adjacent one
So 9/20. To get the degree we need to get the arctan of it, so arctan(9/20) = 24.23
Given:
1 set requires 4 couples 8 dancers.
Total number of people at a square dance = 250.
To find:
The greatest number of sets possible at the dance.
Solution:
We have,
Total people = 250
1 set = 8 people.



Number of possible sets cannot be a decimal or fraction value. So, approx. the value to the preceding integer.

Therefore, the number of possible sets at the dance is 31.