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3 years ago

15

Please help asap 50 pts

2 answers:

PolarNik [594]3 years ago

6 0

B because if you use the equation given and plug a 1 in for the t, you would get 22 which is where the graph is at for 1.

finlep [7]3 years ago

4 0

B because if you use the equation given and plug a 1 in for the t, you would get 22 which is where the graph is at for 1.

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What is the 51st term of the arithmetic sequence 29,9,-11

valina [46]

Answer:

-951

Step-by-step explanation:

an=a1+(n−1)d

\begin{gathered}29 = a_1 + (1-1)d\\29 = a_1\\9 = 29 + (2-1)d\\9 = 29 + d\\d = -20\\a_n = 29 -20 (n-1)\\a_n = 29 - 20n+20\\a_n = -20n + 49\\\\a_51 = -20(51) + 49 = -951\end{gathered}29=a1+(1−1)d29=a19=29+(2−1)d9=29+dd=−20an=29−20(n−1)an=29−20n+20an=−20n+49a51=−20(51)+49=−951

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3 years ago

4. Determine the validity of the following biconditional by

mote1985 [20]

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Step-by-step explanation:

3 0

3 years ago

G(x)= -2x-7 what is g(-3) <br><br> A. -13<br> B. -1 <br> C. -6<br> D. 6

True [87]

You plug -3 into -2x-7 and you get B -1.

4 0

3 years ago

Read 2 more answers

What is the equation, in slope intercept form, for a line parallel to y=-x+11 through point (3,5)?

krek1111 [17]

Answer:

A) y=-x+8

Step-by-step explanation:

Parallel lines have the same slope. So, next you need to find the y-intercept (b) of the line. (see attached work)

5 0

3 years ago

The table of values represents a function f(x).

NeX [460]

Answer:

The average rate of change over the interval [9,10] is greater than that over the interval [5,8] by 6490.

Step-by-step explanation:

The value of f(x) = 4052 for x = 9 and f(x) = 11014 for x = 10.

Therefore, the average rate of change of f(x) with respect to x over the interval [9,10] is given by

= $\frac{\textrm {Total change in value of f(x)}}{\textrm {Total change in value of x}}$

= $\frac{11014 - 4052}{10 - 9} = 6962$

Now, the value of f(x) = 75 for x = 5 and f(x) = 1491 for x = 8.

Therefore, the average rate of change of f(x) with respect to x over the interval [5,8] is given by

= $\frac{\textrm {Total change in value of f(x)}}{\textrm {Total change in value of x}}$

= $\frac{1491 - 75}{8 - 5} = 472$

Therefore, the average rate of change over the interval [9,10] is greater than that over the interval [5,8] by (6962 - 472) = 6490. (Answer)

5 0

3 years ago