Question

bruce has a pet worm that fell into a well. the well is 37 feet deep. each day, the worm climbs up 7 feet, but each night, it slides back down 2 feet. how many days will it take for bruce’s worm to get to the top of the well

Answer 1

In 24 hours, the worm climbs 5 feet.

7-2= 5 (the worm falls 2 feet every night)


So,

5*8=40 

It will take bruce's worm about 8 days to get to the top of the well. 

I hope this helps!
~kaikers

Answer 2

Answer:

7 days.

Step-by-step explanation:

Given,

The depth of the well = 37 feet,

Also, each day, the worm climbs up 7 feet, but each night, it slides back down 2 feet.

Thus, the total vertical distance covered by it in a day = 7 - 2 = 5 feet,

Now, since, at the last 7 feet it will not slide back,

Thus, the distance it has to cover at the rate of 5 feet per day = 37 - 7 = 30 feet,

So, the time taken by it to cover 30 feet = $\frac{30}{5}$ = 6 days,

Hence, the total time taken by it = the time taken by it to cover 30 feet + The time taken to climb up last 7 feet

= 6 days + 1 day

= 7 days.