Let L = length of the swing.

Let the lowest position of the swing be the reference point.
Therefore in the lowest position,
The height of the swing = 0,
The support for the swing is at height = L.

At 32° swing relative to the vertical,
The height of the swing is
A = L - Lcos(32°) = L[1 - cos(32°)] = 0.152L

Answer:
The amplitude is 0.152*L, where L = length of the swing.

6 0

4 years ago

Um pls help<br><br>I really need help

Dima020 [189]

Answer:

1.8L

Explanation:

Boyle's law is a gas law, stating that the pressure and volume of a gas have an inverse relationship. If volume increases, then pressure decreases and vice versa, when the temperature is held constant.

So x is the volume at pressure 235

235x = 101(4.2)

x = 424.2/235 = 1.8

3 0

3 years ago

Two disks are rotating about the same axis. Disk A has a moment of inertia of 3.4 kg m^2 and an angular velocity of 7.2 rad/s. D

lakkis [162]

Answer:

I = 4.4 kg*m^2

Explanation:

As no external torques are present, total angular momentum must be conserved, as follows:

$L_{o} = L_{f} (1)$

The initial angular momentum of the two disks rotating separately, can be written as follows:

$L_{o} =I_{A} * \omega_{oA} + I_{B} * \omega_{oB} (2)$

Replacing by the givens, we get:

$L_{o} = 3.4kg*m2 * 7.2rad/s + I_{B} * (-9.8 rad/s) (3)$

The final angular momentum Lf, as the axis of rotation remains the same, is the product of the moment of inertia of both disks rotating as one, and the common angular velocity ωf, as follows:

$L_{f} = (I_{A} + I_{B}) *\omega_{f} (4)$

Replacing by the givens, we get:

$L_{f} = (3.4 kg*m2 + I_{B} ) * (-2.4 rad/s) (5)$

From (3) and (5), we can solve for IB, as follows:
IB = 4.4 kg*m2

7 0

3 years ago