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3 years ago

A 2 kg mass is attached to a vertical spring and the spring stretches 15 cm from its original relaxed position.

Physics

1 answer:

Naya [18.7K]3 years ago

5 0

Answer:

A. 130.7 N/m

Explanation:

By Hook's law

Force(F) = Spring constant(k) × Extention (d)

F = k× d ⇒ k = F/d

To find Force(F) you know it is the weight of the object. Considering g = 9.8 ms⁻²

k = 2×9.8/0.15 = 130.7 Nm⁻¹

Hooke’s law,

for small deformations of an object, the displacement is directly proportional to the deforming force or load.

Under these conditions the object returns to its original shape and size upon removal of the load.

The deforming force may be applied to a solid by stretching, compressing,etc. so a spring shows an elastic behavior according to Hooke’s law

Mathematically,

applied force( F) = constant (k)* displacement in length (x)

F = kx.

The value of k depends

on the kind of elastic material
on its dimensions and shape.

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Alex is standing still and throws a football with a speed of 10 m/s to his friend, who is also standing still. The two friends a

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The question is incomplete. It comes with a set of answer choices.

These are the answer choices:

Alex observes it as 10 m/s, and his friend observes it as less than 10 m/s.

Alex observes it as less than 10 m/s, and his friend observes it as 10 m/s.

Both Alex and his friend observe it as 10 m/s.

Both Alex and his friend observe it as less than 10 m/s.

Answer: Both Alex and his friend observe it as 10 m/s.

Justification:

1) The speed is relative to the frame of reference.

2) It is said that the both Alex and his friend are standing still.

3) Then, the speed they both see is the same, 10 m/s, respect the Earth (where they are standing still).

Of course, Alex is watching the ball moving away and his friend is seing it approaching, but it is not relevant for the question, as it deals with the speed which is only about magnitude, not direction.

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What are 3 different forces that act on objects on the earth ΩvΩ

Stolb23 [73]

A force is a push or pull acting upon an object as a result of its interaction with another object. There are a variety of types of forces. a variety of force types were placed into two broad category headings on the basis of whether the force resulted from the contact or non-contact of the two interacting objects.

Contact Forces

Action-at-a-Distance Forces

Frictional Force
Gravitational Force
Tensional Force
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3 years ago

Light strikes a 5.0-cm thick sheet of glass at an angle of incidence in air of 50°. the sheet has parallel faces and the glass h

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You collect some more data on that horse at a later time interval, but now you are measuring thehorse’s velocity, not its positi

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Answer:

a) x(t) = 10t + (2/3)*t^3

b) x*(0.1875) = 10.18 m

Explanation:

Note: The position of the horse is x = 2m. There is a typing error in the question. Otherwise, The solution to cubic equation holds a negative value of time t.

Given:

- v(t) = 10 + 2*t^2 (radar gun)

- x*(t) = 10 + 5t^2 + 3t^3 (our coordinate)

Find:

-The position x of horse as a function of time t in radar system.

-The position of the horse at x = 2m in our coordinate system

Solution:

- The position of horse according to radar gun:

v(t) = dx / dt = 10 + 2*t^2

- Separate variables:

dx = (10 + 2*t^2).dt

- Integrate over interval x = 0 @ t= 0

x(t) = 10t + (2/3)*t^3

- time @ x = 2 :

2 = 10t + (2/3)*t^3

0 = 10t + (2/3)*t^3 + 2

- solve for t:

t = 0.1875 s

- Evaluate x* at t = 0.1875 s

x*(0.1875) = 10 + 5(0.1875)^2 + 3(0.1875)^3

x*(0.1875) = 10.18 m

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