Answer:
12x^2y^5
Step-by-step explanation:
Answer:
![(x + (3+5i))^2 = x^2 + 6x + (10x+30)i - 16](https://tex.z-dn.net/?f=%28x%20%2B%20%283%2B5i%29%29%5E2%20%3D%20x%5E2%20%2B%206x%20%2B%20%2810x%2B30%29i%20-%2016)
Step-by-step explanation:
Complex numbers identity:
The complex numbers identity is:
![i^2 = -1](https://tex.z-dn.net/?f=i%5E2%20%3D%20-1)
Square of the sum:
![(x + y)^2 = x^2 + 2xy + y^2](https://tex.z-dn.net/?f=%28x%20%2B%20y%29%5E2%20%3D%20x%5E2%20%2B%202xy%20%2B%20y%5E2)
In this question:
![(x + (3+5i))^2](https://tex.z-dn.net/?f=%28x%20%2B%20%283%2B5i%29%29%5E2)
![x^2 + 2x(3+5i) + (3+5i)^2](https://tex.z-dn.net/?f=x%5E2%20%2B%202x%283%2B5i%29%20%2B%20%283%2B5i%29%5E2)
![x^2 + 6x + 10xi + 9 + 30i + 25i^2](https://tex.z-dn.net/?f=x%5E2%20%2B%206x%20%2B%2010xi%20%2B%209%20%2B%2030i%20%2B%2025i%5E2)
![x^2 + 6x + 9 + (10x+30)i - 25](https://tex.z-dn.net/?f=x%5E2%20%2B%206x%20%2B%209%20%2B%20%2810x%2B30%29i%20-%2025)
![x^2 + 6x + (10x+30)i - 16](https://tex.z-dn.net/?f=x%5E2%20%2B%206x%20%2B%20%2810x%2B30%29i%20-%2016)
So
![(x + (3+5i))^2 = x^2 + 6x + (10x+30)i - 16](https://tex.z-dn.net/?f=%28x%20%2B%20%283%2B5i%29%29%5E2%20%3D%20x%5E2%20%2B%206x%20%2B%20%2810x%2B30%29i%20-%2016)
Answer:
A
Step-by-step explanation:
● first one:
The diagonals of a rhombus are perpendicular to each others wich means that they form four right angles.
STP is one of them so this statement is true.
● second one:
If ST and PT were equal this would be a square not a rhombus.
● third one:
If SPQ was a right angle, this woukd be a square.
● fourth one:
Again if the diagonals SQ and PR were equal, this would be a square.
Answer:
x = 10.58
Step-by-step explanation:
It seems the equation is following
![\frac{2(x+6)3}{\sqrt{5}+3}=19\\\\](https://tex.z-dn.net/?f=%5Cfrac%7B2%28x%2B6%293%7D%7B%5Csqrt%7B5%7D%2B3%7D%3D19%5C%5C%5C%5C)
3 and 2 will simpy multiply and become 6
will go to RHS and will multiply with 19
![6(x+6)= 19(\sqrt{5}+3)\\\\](https://tex.z-dn.net/?f=6%28x%2B6%29%3D%2019%28%5Csqrt%7B5%7D%2B3%29%5C%5C%5C%5C)
6(x+6) will become = 6x + 36
![6x+36 = 19\sqrt{5}+57)\\\\](https://tex.z-dn.net/?f=6x%2B36%20%3D%2019%5Csqrt%7B5%7D%2B57%29%5C%5C%5C%5C)
![6x = 19\sqrt{5}+57-36\\\\](https://tex.z-dn.net/?f=6x%20%3D%2019%5Csqrt%7B5%7D%2B57-36%5C%5C%5C%5C)
![19\sqrt{5} = 42.48](https://tex.z-dn.net/?f=19%5Csqrt%7B5%7D%20%3D%2042.48)
6x = 42.48 + 21
6x = 63.48
x = 10.58
Answer:
25^2
Step-by-step explanation: