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oee [108]
3 years ago
9

How do you know if a given radical expression is a perfect cube?

Mathematics
1 answer:
Natali [406]3 years ago
5 0
If the result of the radical expression is a natural (whole) number
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Find |37|.<br> 0<br> -37<br> 37<br><br><br><br> i have 3 minutes to finish HELPP :(
valentina_108 [34]
It’s -37! | this means the opposite of the number ;)
6 0
3 years ago
Y = 5x – 22<br> 3x + 2y = 34
Anika [276]

Answer:

y = 5x – 22

3x + 2y = 34

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
A. vertical angles<br> b. complementary angle<br> c. supplementary angle<br> d. none of the above
Elis [28]

Answer:

C) supplementary angles

Step-by-step explanation:

C) supplementary angles

They add up to 180.

8 0
3 years ago
Prove that if {x1x2.......xk}isany
Radda [10]

Answer:

See the proof below.

Step-by-step explanation:

What we need to proof is this: "Assuming X a vector space over a scalar field C. Let X= {x1,x2,....,xn} a set of vectors in X, where n\geq 2. If the set X is linearly dependent if and only if at least one of the vectors in X can be written as a linear combination of the other vectors"

Proof

Since we have a if and only if w need to proof the statement on the two possible ways.

If X is linearly dependent, then a vector is a linear combination

We suppose the set X= (x_1, x_2,....,x_n) is linearly dependent, so then by definition we have scalars c_1,c_2,....,c_n in C such that:

c_1 x_1 +c_2 x_2 +.....+c_n x_n =0

And not all the scalars c_1,c_2,....,c_n are equal to 0.

Since at least one constant is non zero we can assume for example that c_1 \neq 0, and we have this:

c_1 v_1 = -c_2 v_2 -c_3 v_3 -.... -c_n v_n

We can divide by c1 since we assume that c_1 \neq 0 and we have this:

v_1= -\frac{c_2}{c_1} v_2 -\frac{c_3}{c_1} v_3 - .....- \frac{c_n}{c_1} v_n

And as we can see the vector v_1 can be written a a linear combination of the remaining vectors v_2,v_3,...,v_n. We select v1 but we can select any vector and we get the same result.

If a vector is a linear combination, then X is linearly dependent

We assume on this case that X is a linear combination of the remaining vectors, as on the last part we can assume that we select v_1 and we have this:

v_1 = c_2 v_2 + c_3 v_3 +...+c_n v_n

For scalars defined c_2,c_3,...,c_n in C. So then we have this:

v_1 -c_2 v_2 -c_3 v_3 - ....-c_n v_n =0

So then we can conclude that the set X is linearly dependent.

And that complet the proof for this case.

5 0
3 years ago
What is the value of x in simplest radical form?
Vikki [24]

Answer:

It's 90 because we'll make it equal

5 0
3 years ago
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