Which liquid is the most viscous?
2 answers:
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<u>Answer:</u> The change in entropy of the given process is 1324.8 J/K
<u>Explanation:</u>
The processes involved in the given problem are:
Pressure is taken as constant.
To calculate the entropy change for same phase at different temperature, we use the equation:
.......(1)
where,
= Entropy change
= specific heat capacity of medium
m = mass of ice = 0.15 kg = 150 g (Conversion factor: 1 kg = 1000 g)
= final temperature
= initial temperature
To calculate the entropy change for different phase at same temperature, we use the equation:
.......(2)
where,
= Entropy change
m = mass of ice
= enthalpy of fusion of vaporization
T = temperature of the system
Calculating the entropy change for each process:
- <u>For process 1:</u>
We are given:
Putting values in equation 1, we get:
- <u>For process 2:</u>
We are given:
Putting values in equation 2, we get:
- <u>For process 3:</u>
We are given:
Putting values in equation 1, we get:
- <u>For process 4:</u>
We are given:
Putting values in equation 2, we get:
- <u>For process 5:</u>
We are given:
Putting values in equation 1, we get:
Total entropy change for the process =
Total entropy change for the process =
Hence, the change in entropy of the given process is 1324.8 J/K