A ball is dropped off a building and falls past a window that is 2.2m long. If it takes .28s for the ball to cross the window wh
at is the distance from the top of the building to the top of the window?
1 answer:
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Answer:
The helicopter was 1103.63 meters high when the package was dropped.
Explanation:
We consider positive speed as a downward movement
y: height (m)
t: time (s)
v₀: initial speed (m/s)
Δy = v₀t + gt²
Δy= 15×15 s +
×9.81
×(15 s)²
Δy= 1103.63 m