Answer:
The magnitude of the electric field are
and 
Explanation:
Given that,
Radius of inner shell = 11.0 cm
Radius of outer shell = 14.0 cm
Charge on inner shell 
Charge on outer shell 
Suppose, at r = 11.5 cm and at r = 20.5 cm
We need to calculate the magnitude of the electric field at r = 11.5 cm
Using formula of electric field

Where, q = charge
k = constant
r = distance
Put the value into the formula


The total charge enclosed by a radial distance 20.5 cm
The total charge is

Put the value into the formula


We need to calculate the magnitude of the electric field at r = 20.5 cm
Using formula of electric field

Put the value into the formula


Hence, The magnitude of the electric field are
and 
M = mass of aluminium = 1.11 kg
= specific heat of aluminium = 900
= initial temperature of aluminium = 78.3 c
m = mass of water = 0.210 kg
= specific heat of water = 4186
= initial temperature of water = 15 c
T = final equilibrium temperature = ?
using conservation of heat
Heat lost by aluminium = heat gained by water
M
(
- T) = m
(T -
)
(1.11) (900) (78.3 - T) = (0.210) (4186) (T - 15)
T = 48.7 c
Answer:
Sound waves transfer energy by causing successive compressions and rarefactions in the particles of the medium without transporting the medium particles themselves. Sound in solids can also manifest as transverse waves, causing crests and troughs in the propagation medium.
So we can know what is in space maybe weird or interesting stuff
Answer:
The theory is supported by all the available observations and data.
Explanation: The scientific community will accept a theory when a sufficient body of evidence supports it. This includes experiments that refute other potential theories. Experiments should also be carried out that attempt to disprove the theory but cannot.
It should not matter who proposed the theory or who supports it, and instead should entirely be based on the quality and abundance of data supporting it.
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