If Siobhan hits a 0.25 kg volleyball with 0.5 N of force, what is the acceleration of the ball?
2 answers:
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Answer:
The value is
Explanation:
From the question we are told that
The length of the crack is
The frequency is
The distance outside the cave that is being consider is
The speed of sound is
Generally the wavelength of the wave is mathematically represented as
=>
=>
Generally for a single slit the path difference between the interference patterns of the sound wave and the center is mathematically represented as
=>
=>
Generally the width of the sound beam is mathematically represented as
=>
=>
Missing details: figure of the problem is attached.
We can solve the exercise by using Poiseuille's law. It says that, for a fluid in laminar flow inside a closed pipe,
where:
is the pressure difference between the two ends
is viscosity of the fluid
L is the length of the pipe
is the volumetric flow rate, with
being the section of the tube and
the velocity of the fluid
r is the radius of the pipe.
We can apply this law to the needle, and then calculating the pressure difference between point P and the end of the needle. For our problem, we have:
is the dynamic water viscosity at
L=4.0 cm=0.04 m
and r=1 mm=0.001 m
Using these data in the formula, we get:
However, this is the pressure difference between point P and the end of the needle. But the end of the needle is at atmosphere pressure, and therefore the gauge pressure (which has zero-reference against atmosphere pressure) at point P is exactly 3200 Pa.
