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3 years ago

6

A 30 kg child went down a 10 m tall slide. Assuming no energy was lost as friction, what was the child's velocity when he reache

d the
bottom?
I

1 answer:

AveGali [126]3 years ago

5 0

14 m/s or 50km/h. See the details in the attached picture.

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The magnitude of the electrical force acting between a +2.4 x 10- C charge and a +1.8 x 10- C charge that are separated

Brrunno [24]

Answer: 6.07 N

Explanation:

According to Coulomb's Law:

$F_{E}= K\frac{q_{1}.q_{2}}{d^{2}}$

Where:

$F_{E}$ is the electrostatic force

$K=8.99(10)^{9} Nm^{2}/C^{2}$ is the Coulomb's constant

$q_{1}=2.4(10)^{-8} C$ and $q_{2}=1.8(10)^{-6} C$ are the electric charges

$d=0.008 m$ is the separation distance between the charges

Solving:

$F_{E}= 8.99(10)^{9} Nm^{2}/C^{2}\frac{(2.4(10)^{-8} C)(1.8(10)^{-6} C)}{(0.008 m)^{2}}$

$F_{E}=6.07 N$

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3 years ago

A hair dryer required 12 V to operate properly. When plugged into a 120 V outlet, a transformer must change voltage. If the prim

grigory [225]

Answer:

5.7 turns

Explanation:

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2 years ago

3. What is the power of a derby race car that uses a 50 N force to travel 20 meters in 10 seconds?

makkiz [27]

I think it is B. 100 W

7 0

3 years ago

A 0.48 kg circus monkey is about to be shot from a cannon as part of his thrilling circus act. Draw a free body diagram labeling

Alenkinab [10]

What is it that you need help on?

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2 years ago

A 1451 kg car is traveling at 48.0 km/h. How much kinetic energy does it possess? K.E. =

jarptica [38.1K]

   Kinetic energy = (1/2) (mass) (speed)²

BUT . . . in order to use this equation just the way it's written,
the speed has to be in meters per second. So we'll have to
make that conversion.

KE = (1/2) · (1,451 kg) · (48 km/hr)² · (1000 m/km)² · (1 hr/3,600 sec)²

   = (725.5) · (48 · 1000 · 1 / 3,600)² (kg) · (km·m·hr / hr·km·sec)²

   = (725.5) · ( 40/3 )² · ( kg·m² / sec²)

   = 128,978 joules (rounded)

8 0

2 years ago