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Zolol [24]
4 years ago
15

What is the range of the function on the graph?

Mathematics
1 answer:
Paladinen [302]4 years ago
6 0
All real numbers less than or equal to 3
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3 years ago
7 less than 34 of a number is greater than or equal to 23​
Naya [18.7K]

Answer:

equal to

Step-by-step explanation:

4 0
3 years ago
I'm having a bit of a problem with this piecewise function I will upload a photo
kipiarov [429]

Given the piecewise function:

f(x)=\begin{cases}-0.5x-4,x\le-2 \\ 5,-24\end{cases}

So, for the given function, we will graph it as follows:

1) graph the line (-0.5x-4) as x less than or equal to -2

To graph the line, we need two points

We will substitute with two values less than -2 and calculate the corresponding values of f(x)

When x = -4, f(x) = -0.5 * -4 - 4 = -2

When x = -6, f(x) = -0.5 * -6 - 4 = -1

So, the line will pass through the points ( -4, -2) and ( -6, -1)

The line will start from the point ( -2, -3)

The dot at x = -2 will be closed.

2) Graph the line (y = 5) as x between -2 and 4

The line will be horizontal at this interval

the dot at x = -2 will be open

The dot at x = 4 will be closed

3) Graph the line ( -x + 5 ) as x greater than 4

As in (1), substitute with 2 values of x greater than 4

When x = 5, f(x) = -5 + 5 = 0

When x = 6, f(x) = -6 + 5 = -1

So, the line will pass through the points ( 5, 0 ) and ( 6, -1 )

The graph of the function will be as shown in the following picture:

8 0
1 year ago
Which expressions are equivalent to 42-5? Choose all the correct answers. Show your work in arriving at your answers.
frozen [14]

Answer:

B, C, E

Step-by-step explanation:

<u />

<u>Exponent Rules</u>

a^b \cdot a^c=a^{b+c}

\dfrac{a^b}{a^c}=a^{b-c}

a^n \cdot b^n=(ab)^n

a^0=1

\dfrac{1}{a^b}=a^{-b}

(a^b)^c=a^{bc}

\textsf{A}\quad42^{-3} \cdot 42^8=42^{-3+8}=42^5

\textsf{B}\quad \dfrac{42^{-7}}{42^{-2}}=42^{-7-(-2)}=42^{-5}

\textsf{C}\quad \dfrac{6^{-5}}{7^5}=6^{-5} \cdot 7^{-5}=(6 \cdot 7)^{-5}=42^{-5}

\textsf{D}\quad 42^0 \cdot 42^5=1 \cdot 42^5=42^5

\textsf{E}\quad \left(\dfrac{1}{42^{-5}}\right)^{-1}=(42^5)^{-1}=42^{-5}

\textsf{F}\quad \left(\dfrac{6^{-5}}{7^5}\right)^{-1}=\left(6^{-5} \cdot 7^{-5}\right)^{-1}=\left(\left(6 \cdot 7\right)^{-5}\right)^{-1}=42^{-5(-1)}=42^5

3 0
2 years ago
Read 2 more answers
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