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2 years ago

13

If (2y^4z^m)^8 what is m

2 answers:

Feliz [49]2 years ago

5 0

Please see attached image for the answer

aksik [14]2 years ago

4 0

M is the exponent of z inside parentheses. In expanded form, the exponent of z is 8m, so m is 1/8 of the exponent of z.

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AD = 3x + 4 and CD = x + 6, what is the value of x?

lesantik [10]

Your answer would be x = 1.

The rules for a kite shape is that two pairs are of equal length, which means we can say that AD = CD and thus form an equation:

3x + 4 = x + 6
- x
2x + 4 = 6
- 4
2x = 2
÷ 2
x = 1

I hope this helps!

5 0

2 years ago

Franco has 7 quarters in his pocket. Of these, 3 depict the state of Delaware, 2 depict Georgia, 1 depicts Connecticut and 1 dep

tiny-mole [99]

2/6

because after you take one quarter out you have a total of 6 left & you have 3 delaware ones and you already have 1 delaware one out of your pocket it makes it 2/6

6 0

2 years ago

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Vika [28.1K]

Answer:

Ok hi

Step-by-step explanation:

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2 years ago

Tanya's father travels every week for business. He has traveled around the

Nikitich [7]

The correct answer would be: 4.6 x 10^5

8 0

2 years ago

Let A and B be events with =PA0.7, =PB0.3, and =PA or B0.9. (a) Compute PA and B. (b) Are A and B mutually exclusive? Explain. (

kvasek [131]

Answer:

a) $P(A \cup B) = P(A) +P(B) - P(A\cap B)$

And if we solve for $P(A \cap B)$ we got:

$P(A \cap B) = P(A) + P(B) -P(A\cup B)= 0.7+0.3-0.9 = 0.1$

b) False

The reason is because we don't satisfy the following relationship:

$P(A\cup B) = P(A) + P(B)$

We have that:

$0.9 \neq 0.3+0.7 =1$

c) False

In order to satisfy independence we need to have the following condition:

$P(A \cap B) = P(A) *P(B)$

And for this case we don't satisfy this relation since:

$0.1 \neq 0.7*0.3 = 0.21$

Step-by-step explanation:

For this case we have the following probabilities given:

$P(A) = 0.7, P(B) =0.7, P(A \cup B) =0.9$

Part a

We want to calculate the following probability: $P(A \cap B)$

And we can use the total probability rule given by:

$P(A \cup B) = P(A) +P(B) - P(A\cap B)$

And if we solve for $P(A \cap B)$ we got:

$P(A \cap B) = P(A) + P(B) -P(A\cup B)= 0.7+0.3-0.9 = 0.1$

Part b

False

The reason is because we don't satisfy the following relationship:

$P(A\cup B) = P(A) + P(B)$

We have that:

$0.9 \neq 0.3+0.7 =1$

Part c

False

In order to satisfy independence we need to have the following condition:

$P(A \cap B) = P(A) *P(B)$

And for this case we don't satisfy this relation since:

$0.1 \neq 0.7*0.3 = 0.21$

4 0

3 years ago