<em>The statement that gives the relationship between energy needed in breaking a bond and the one that is released after breakin</em>g is
The amount of energy it takes to break a bond is always less than the amount of energy released when the bond is formed.
- Bond energy can be regarded as amount of energy that is required in breaking a particular bond.
- For a bond to be broken Energy will be added and when a bond is broken there will be release of energy
- Bond breaking can be regarded as endothermic process, it is regarded as endothermic because there is a lot of energy required to be absorbed.
- Where ever a bond is broken, there must be formation of another bond
- Bond forming on the other hand can be regarded as exothermic process, since there is a release of releases energy.
Therefore, more energy is required in breaking of bond compare to energy released after breaking of bond.
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Relative energies are in the order:
s < p < d < f
And the shape of these orbitals are
s - spherical
p - dumbbell
d - double dumbbell
f - double double dumbbell
Molecular weight of N2
gram Atomic weight of N is 14 g.
gram Molecular weight = 14 g×2
= 28 g
Liter concepts
1 liter of gas always occupies 1 gram molecular weight .
Application of the concept
5.75 liter gives 0.257g
1 mole will occupy 28 g
0.257 will occupy 28 g × 0.257
= 7.196 g
The mass of the gas is 7.196 g.
Hope it helps you
Planck suggested that light/energy was absorbed/released in certain amounts, called quanta.
Answer:
b. Beta emission, beta emission
Explanation:
A factor to consider when deciding whether a particular nuclide will undergo this or that type of radioactive decay is to consider its neutron:proton ratio (N/P).
Now let us look at the N/P ratio of each atom;
For B-13, there are 8 neutrons and five protons N/P ratio = 8/5 = 1.6
For Au-188 there are 109 neutrons and 79 protons N/P ratio = 109/79=1.4
For B-13, the N/P ratio lies beyond the belt of stability hence it undergoes beta emission to decrease its N/P ratio.
For Au-188, its N/P ratio also lies above the belt of stability which is 1:1 hence it also undergoes beta emission in order to attain a lower N/P ratio.
