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Schach [20]
3 years ago
10

What is the overall equation for FeCl3(aq) + NH3(aq) + H2O(l)? the overall ionic equation? then the net ionic equation?

Chemistry
2 answers:
diamong [38]3 years ago
4 0
So the question ask to calculate the over all equation for a certain element and the following are 
- over all equation -  FE(OH)3+3NH4CI
- over all ionic equation -  e(OH)3 (s) & 3 NH4+ (aq) & 3Cl- (aq) - net ionic equation -  Fe+3+3OH-+3NH$++3CI-
Amanda [17]3 years ago
4 0

<u>Answer:</u> The net ionic equation is written below.

<u>Explanation:</u>

Net ionic equation of any reaction does not include any spectator ions.

Spectator ions are defined as the ions which does not get involved in a chemical equation. They are found on both the sides of the chemical reaction when it is present in ionic form.

The chemical equation for the reaction of iron(III) chloride, ammonia and water is given as:

FeCl_3(aq.)+3NH_3(g)+3H_2O(l)\rightarrow Fe(OH)_3(s)+3NH_4Cl(aq.)

Ionic form of the above equation follows:

Fe^{3+}(aq.)+3Cl-(aq.)+3NH_3(g)+3H_2O(l)\rightarrow Fe(OH)_3(s)+3NH_4^+(aq.)+3Cl^-(aq.)

As, chloride ions are present on both the sides of the reaction. Thus, it will not be present in the net ionic equation and is the spectator ion.

The net ionic equation for the above reaction follows:

Fe^{3+}(aq.)+3NH_3(g)+3H_2O(l)\rightarrow Fe(OH)_3(s)+3NH_4^+(aq.)

Hence, the net ionic equation is written above

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3 years ago
If 5. 0 grams of kcl is dissolved in 500 ml of water, what is the concentration of the resulting solution?
Lady_Fox [76]

If 5.0 grams of KCl is dissolved in 500 ml of water, the concentration of the resulting solution will be 0.134M.

<h3>How to calculate concentration?</h3>

The concentration of a solution can be calculated by using the following formula;

Molarity = no of moles ÷ volume

According to this question, 5.0 grams of KCl is dissolved in 500 ml of water. The concentration is calculated as follows:

no of moles of KCl = 5g ÷ 74.5g/mol = 0.067mol

Molarity = 0.067mol ÷ 0.5L = 0.134M

Therefore, if 5.0 grams of KCl is dissolved in 500 ml of water, the concentration of the resulting solution will be 0.134M.

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6 0
2 years ago
Define ""point source pollution"" and ""non-point pollution"".
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A 50 gram sample of a radioisotope undergoes 2 half-lives. How many grams
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