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Valentin [98]
3 years ago
12

3. Give three examples of a pure substances

Chemistry
2 answers:
liq [111]3 years ago
7 0
Tin, sulfur, and water
Nadya [2.5K]3 years ago
5 0

Answer:

There will be weight, there will be volume, there will be height

Explanation:

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The absorbance of a cationic iron(II) sample solution was measured in a spectrophotometer, but the instrument returned an error
JulijaS [17]

Answer:

1.35\times 10^{-4} M was the concentration of the original solution.

Explanation:

M_1V_1=M_2V_2  (Dilution)

where,

M_1\text{ and }V_1 are molarity and volume of non diluted sample.

M_2\text{ and }V_2 are molarity and volume of diluted sample.

M_1=?

V_1=100.0 \mu L=0.1 mL

(1μL=0.001  mL)

M_2=6.41\times 10^{-6} M

V_2=2.00 mL + 100.0 \mu L=2.00 mL+0.1 mL=2.1 mL

Substituting all values :

M_1\times 0.1 mL=6.41\times 10^{-6} M\times 2.1 mL

M_1=\frac{6.41\times 10^{-6} M\times 2.1 mL}{0.1 mL}=1.35\times 10^{-4} M

1.35\times 10^{-4} M was the concentration of the original solution.

5 0
3 years ago
What is mean by stakeholder​
NemiM [27]

Answer:

  • a stakeholder is a party that has an interest in a company and can either effect or be affected by the business. the primary stakeholder in a typical corporation are its <u><em>investors </em></u>, employees, customers and supplies.

5 0
4 years ago
What does the answer of element 3Na2S2O3?
Fynjy0 [20]

Answer:

Explanation:

3× 22+2×32+ 6×16=

66+64+96=236

4 0
3 years ago
The decomposition of hydrogen peroxide, H2O2, has been used to provide thrust in the control jets of various space vehicles. Usi
lesantik [10]

Answer:

\Delta H^0 _{reaction} = - 54.04 \ kJ/mol

Explanation:

The given equation for the chemical reaction can be expressed as;

2H_2O_{(l)}  \to 2H_2O_{(g)} +  O_{2(g)}

Using Hess Law to determine how much heat is produced by the decomposition of exactly 1 mole of H2O2 under standard conditions; we have the expression showing the Hess Law as follows:

\Delta H^0 _{reaction} = \sum n* \Delta H^0 _{products} -  \sum n* \Delta H^0 _{reactants}

At standard conditions;

the molar enthalpies of the given equation are as follows:

\Delta H_2O_{(g)} =-241.82\ kJ/mol

\Delta H_  O_{2(g)} = 0 \ kJ/mol

\Delta H _{H_2O_{(l)}}= -187.78  \ kJ/mol

Replacing them into above formula; we have:

\Delta H^0 _{reaction} = (2*(-241.82\ kJ/mol) + 0 \ kJ/mol + (2 *(-187.78 \ kJ/mol))

\Delta H^0 _{reaction} =-108.08 \ kJ/mol

The above is the amount of heat of formation for two moles of hydrogen peroxide; thus for 1 mole hydrogen peroxide ; we have :

\Delta H^0 _{reaction} = \dfrac{-108.08 \ kJ/mol}{2}

\Delta H^0 _{reaction} = - 54.04 \ kJ/mol

Hence; the heat produced after the decomposition of 1 mole of hydrogen peroxide is -54.04 kJ/mol

6 0
4 years ago
Can somebody explain this?
STatiana [176]

Answer:

Hydrogen idodie is formed (HI)

6 product molecules formed

Limiting reactant (like the name,it means what is limited,in other words, it means it is lacking of , which is hydrogen in this case)

while iodine is in excess

6 0
3 years ago
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