The empirical formula : C₂Cl₇
The molecular formula : C₁₀Cl₃₅
<h3>Further explanation</h3>
Given
8.81 g Carbon
91.2 g Chlorine
Molar Mass: 1362.5 g/mol
Required
The empirical formula and molecular formula
Solution
Mol ratio :
C = 8.81 g : 12.011 g/mol =0.733
Cl = 91.2 g : 35,453 g/mol = 2..572
Divide by 0.733
C : Cl = 1 : 3.5 = 2 : 7
The empirical formula : C₂Cl₇
(The empirical formula)n = the molecular formula
(C₂Cl₇)n = 1362.5
(2x12.011+7x35.453)n=1362.5
(272.193)n=1362.5
n = 5
The rate constant : k = 9.2 x 10⁻³ s⁻¹
The half life : t1/2 = 75.3 s
<h3>Further explanation</h3>
Given
Reaction 45% complete in 65 s
Required
The rate constant and the half life
Solution
For first order ln[A]=−kt+ln[A]o
45% complete, 55% remains
A = 0.55
Ao = 1
Input the value :
ln A = -kt + ln Ao
ln 0.55 = -k.65 + ln 1
-0.598=-k.65
k = 9.2 x 10⁻³ s⁻¹
The half life :
t1/2 = (ln 2) / k
t1/2 = 0.693 : 9.2 x 10⁻³
t1/2 = 75.3 s
The molar mass of NH4NO3 in g/mol is 80g/mol.
HOW TO CALCULATE MOLAR MASS:
The molar mass of a compound can be calculated by summing the atomic masses of its constituent elements.
In ammonium nitrate (NH4NO3), there are nitrogen, hydrogen, and oxygen elements.
- Atomic mass of nitrogen = 14
- Atomic mass of oxygen = 16
- Atomic mass of hydrogen = 1
Molar mass of NH4NO3 = 14 + 1(4) + 14 + 16(3)
Molar mass of NH4NO3 = 80g/mol
- Therefore, the molar mass of NH4NO3 in g/mol is 80g/mol.
Learn more about molar mass at: brainly.com/question/8101390?referrer=searchResults
