Is my answer correct or no?

Physics

2 answers:

irinina [24]3 years ago

8 0

No your answer is incorrect. Would you like the correct one?

OLEGan [10]3 years ago

8 0

Your answer is incorrect would you like me to help you or do you think you can figure it out on your own

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Ask Your Teacher A flight attendant pulls her 69 N flight bag a distance of 268 m along a level airport floor at a constant velo

Simora [160]

Answer:

a) W = 5360 J b) μ = 0.29

Explanation:

a) The work is, bold indicate vectors

W = F. d = F d cos T

W = 40 268 cos 60

W = 5360 J

b) The force of friction and opposes the movement of the body and if the speed of the body is constant implies that the external force in the direction of the movement is equal to the force of friction, or which work is the same

$W_{fr}$ = -5360J

The negative sign is because the force of friction is contrary to the direction of movement

c) Let's write the work of the friction force

$W_{fr}$ = fr d cos 180

fr = μ N

Since the body is on a horizontal surface, from Newton's second law on the Y axis

N-W = 0

N = W

fr = μ W

$W_{fr}$ = - μ W d

μ = - $W_{fr}$ / W d

μ = - (-5360) / 69 268

μ = 0.29

7 0

3 years ago

Julianne went to a restaurant to have a taste of her favorite fried chicken and spaghetti. She drove 2 km, east and then 8.5 km,

GREYUIT [131]

Julianne’s displacement from her origin is equal to 10.015 kilometers.

Given the following data:

Distance A = 2 km, East.

Distance B = 8.5 km, Northeast.

To calculate Julianne’s displacement from her origin:

<h3>How to calculate displacement.</h3>

We would denote the two (2) unit vectors along the East and Northeast directions by i and j respectively.

Note: Northeast is at angle of 45° with the East.

In terms of vectors, the distances becomes:

Distance A = 2i

$Distance\;B=8.5 [(cos 45i + sin 45j)]\\\\Distance\;B=(\frac{8.5}{\sqrt{2} } i \;+\;\frac{8.5}{\sqrt{2} } j)$

For the resultant displacement:

$D^2 = [(2+\frac{8.5}{\sqrt{2} } )^2+ (\frac{8.5}{\sqrt{2} } )^2\\\\D =\sqrt{[(2+\frac{8.5}{\sqrt{2} } )^2+ (\frac{8.5}{\sqrt{2} } )^2} \\\\D=2+\frac{8.5}{\sqrt{2} } + \frac{8.5}{\sqrt{2} }$