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AlladinOne [14]
3 years ago
15

For an isothermal process, the work done by or on a system of ideal gas is equal to the change in what?

Physics
1 answer:
morpeh [17]3 years ago
5 0

Explanation:

The equation for work done by a system is as follows.

                \Delta U = Q - W

where,    \Delta U = change in internal energy

                          Q = heat absorbed or released by the system

                          W = work done by the system

Since it is given that it is an isothermal process. Therefore, \Delta T = 0.

Whereas internal energy depends on temperature and as there is no change in temperature so, there will be no change in internal energy of the system.

Hence, the equation will be as follows.

                     \Delta U = Q - W

                               0 = Q - W

                               Q = W

Therefore, we can conclude that for an isothermal process, the work done by or on a system of ideal gas is equal to the change in Q.

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An object is placed perpendicular to the the principal axis of convex lens of focal length 8,the distance of the object from the
Digiron [165]

Answer:

v = 24 cm and inverted image

Explanation:

Given that,

The focal length of the object, f = +8 cm

Object distance, u = -12 cm

We need to find the position &nature of the image​. Let v be the image distance. Using lens formula to find it :

\dfrac{1}{v}-\dfrac{1}{u}=\dfrac{1}{f}

Put all the values,

\dfrac{1}{v}=\dfrac{1}{f}+\dfrac{1}{u}\\\\\dfrac{1}{v}=\dfrac{1}{8}+\dfrac{1}{(-12)}\\\\v=24\ cm

So, the image distance from the lens is 24 cm.

Magnification,

m=\dfrac{v}{u}\\\\m=\dfrac{24}{-12}\\\\m=-2

The negative sign of magnification shows that the formed image is inverted.

7 0
3 years ago
Two piano strings produce beats. Frequencies of the strings are 1560 Hz. and 1563 Hz. Choose the correct frequency of the beats.
kakasveta [241]

Beat frequency is given by the difference of two frequencies played together

f_{beat} = |f_1 - f_2|

given that

f_1 = 1560 Hz

f_2 = 1563 Hz

Now

f_{beat} = |1560- 1563| Hz

f_{beat} = 3 Hz

3 0
3 years ago
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Which are disadvantages of series circuits? Check all that apply.
11Alexandr11 [23.1K]

Answer:

C and F

Explanation:

A break in one wire causes all current to stop.

If one bulb goes out, the others go out.

5 0
3 years ago
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A person with mass mp = 74 kg stands on a spinning platform disk with a radius of R = 2.31 m and mass md = 183 kg. The disk is i
timurjin [86]

Answer:

1) 883 kgm2

2) 532 kgm2

3) 2.99 rad/s

4) 944 J

5) 6.87 m/s2

6) 1.8 rad/s

Explanation:

1)Suppose the spinning platform disk is solid with a uniform distributed mass. Then its moments of inertia is:

I_d = m_dR^2/2 = 183*2.31^2/2 = 488 kgm^2

If we treat the person as a point mass, then the total moment of inertia of the system about the center of the disk when the person stands on the rim of the disk:

I_{rim} = I_d + m_pR^2 = 488 + 74*2.31^2 = 883 kgm^2

2) Similarly, he total moment of inertia of the system about the center of the disk when the person stands at the final location 2/3 of the way toward the center of the disk (1/3 of the radius from the center):

I_{R/3} = I_d + m_p(R/3)^2 = 488 + 74*(2.31/3)^2 = 532 kgm^2

3) Since there's no external force, we can apply the law of momentum conservation to calculate the angular velocity at R/3 from the center:

I_{rim}\omega_{rim} = I_{R/3}\omega_{R/3}

\omega_{R/3} = \frac{I_{rim}\omega_{rim}}{I_{R/3}}

\omega_{R/3} = \frac{883*1.8}{532} = 2.99 rad/s

4)Kinetic energy before:

E_{rim} = I_{rim}\omega_{rim}^2/2 = 883*1.8^2/2 = 1430 J

Kinetic energy after:

E_{R/3} = I_{R/3}\omega_{R/3}^2/2 = 532*2.99^2/2 = 2374 J

So the change in kinetic energy is: 2374 - 1430 = 944 J

5) a_c = \omega_{R/3}^2(R/3) = 2.99^2*(2.31/3) = 6.87 m/s^2

6) If the person now walks back to the rim of the disk, then his final angular speed would be back to the original, which is 1.8 rad/s due to conservation of angular momentum.

3 0
3 years ago
A polo player hits a ball with a mass of 0.42 kg with a force of 7.35 Newtons.
Serga [27]
Due to the law of conservation of momentum, the force exerted on the mallet is equal and opposite to the force exerted on the ball, so the answer is C.
4 0
3 years ago
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