For an isothermal process, the work done by or on a system of ideal gas is equal to the change in what?
1 answer:
Explanation:
The equation for work done by a system is as follows.
where, = change in internal energy
Q = heat absorbed or released by the system
W = work done by the system
Since it is given that it is an isothermal process. Therefore, .
Whereas internal energy depends on temperature and as there is no change in temperature so, there will be no change in internal energy of the system.
Hence, the equation will be as follows.
0 = Q - W
Q = W
Therefore, we can conclude that for an isothermal process, the work done by or on a system of ideal gas is equal to the change in Q.
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Answer:
Explanation:
<u>Conservation of Momentum </u>
The total momentum of a system of two particles is
Where m1,m2,v1, and v2 are the respective masses and velocities of the particles at a given time. Then, the two particles collide and change their velocities to v1' and v2'. The final momentum is now
The momentum is conserved if no external forces are acting on the system, thus
Let's put some numbers in the problem and say
120=120
It means that when the particles collide, the first mass returns at 6 m/s and the second continues in the same direction at 28 m/s