3 years ago

What movement allows us to move our side to side?

Physics

1 answer:

mezya [45]3 years ago

4 0

Answer:

Ball-and-socket joints

Explanation:

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When a calcium atom forms an ion, it loses two electrons. What is the electrical charge of the calcium ion? a) −2 b) −1 c)+ 1 d)

MrRa [10]

Answer:

Option D

Explanation:

We know that Calcium has 20 electrons and 20 protons. It lost two electrons, it has 20 protons, but only 18 electrons. This makes calcium a positive ion with a charge of +2.

8 0

2 years ago

A beaker of negligible heat capacity contains 456 g of ice at -25.0°C. A lab technician begins to supply heat to the container a

Scorpion4ik [409]

Answer:

176 min

Explanation:

456 g = .456 kg

Specific heat of ice s = 2093 J kg⁻¹

Heat required to raise the temperature by 25 degree

= mass x specific heat x rise in temperature.

= .456 x 2093 x 25

=23860 J

Heat required to melt the ice to make water at zero degree

= mass x latent heat

= .456 x 334 x 10³

=152304 J

Total heat required = 152304 + 23860 = 176164 J .

Time Required = Heat required / rate of supply of heat

= 176164 / 1000

176.16 min

4 0

2 years ago

Cuál es la resistencia de un foco que está conectado a una fuente de 20 v por el cuál pasa una intensidad de 20 mA

LUCKY_DIMON [66]

Answer:

The resistance of the bulb is 1000 ohms.

Explanation:

What is the resistance of a bulb that is connected to a 20 v source through which a current of 20 mA passes

We have,

Voltage of the bulb is 20 V and the current passes is 20 mA.

It is required to find the resistance of the bulb. The relation between resistance, current and voltage is given by using Ohm's law as :

V = IR

R is resistance

$R=\dfrac{V}{I}\\\\R=\dfrac{20}{20\times 10^{-3}}\\\\R=1000\ \Omega$

So, the resistance of the bulb is 1000 ohms.

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2 years ago

Tissues types<br> Please help

Harlamova29_29 [7]

Answer:

Explanation: what grade are u in?

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2 years ago

A sealed syringe contains 10 × 10−6 m3 of air at 1 × 105 Pa. The plunger is pushed until the volume of trapped air is 4 × 10−6 m

Scilla [17]

Answer: $P_2=2.5\times 10^5\ Pa$

Explanation:

Given

Initial volume $V_1=10\times 10^{-6}\ m^3$

Initial Pressure $P_1=10^5\ Pa$

Final trapped air $V_2=4\times 10^{-6}\ m^3$

If there is no change in temperature then We can write

$P_1V_1=P_2V_2\quad \text{(From ideal gas equation)}$

$P_2=\dfrac{P_1V_1}{V_2}$

$P_2=10^5\times \frac{10\times 10^{-6}}{4\times 10^{-6}}$

$P_2=2.5\times 10^5\ Pa$

6 0

3 years ago