Force = mass * acceleration
mass = Force/acceleration
= 36/2
mass = 18 kg
B = magnetic field in the cyclotron = 0.400 T
q = magnitude of charge on a proton = 1.6 x 10⁻¹⁹ C
m = mass of the proton = 1.67 x 10⁻²⁷ kg
f = frequency of revolution of proton in the cyclotron = ?
v = speed of electromagnetic waves = 3 x 10⁸ m/s
λ = wavelength of electromagnetic wave = ?
Frequency of revolution of proton in the cyclotron is given as
f = qB/(2πm)
inserting the values
f = (1.6 x 10⁻¹⁹)(0.400)/(2 (3.14) (1.67 x 10⁻²⁷))
f = 6.1 x 10⁶ Hz
wavelength of electromagnetic wave is given as
λ = v/f
λ = (3 x 10⁸)/(6.1 x 10⁶)
λ = 49.2 m
Answer:
Vertical component of velocity is 9.29 m/s
Explanation:
Given that,
Velocity of projection of a projectile, v = 22 m/s
It is fired at an angle of 22°
The horizontal component of velocity is v cosθ
The vertical component of velocity is v sinθ
So, vertical component is given by :
Hence, the vertical component of the velocity is 9.29 m/s
F = m*a
a = v/t
a = 9.0 m/s / 2.0 s
a = 4.5 m/s^2
F = 100 kg * 4.5 m/s^2
F = 450 N
Sig figs = 500 N?
The answer is B. magnesium I am pretty sure
