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3 years ago

Hita's Question Bank- CTEVTBaishakh] Q.No. 12 What is radiocarbon dating?VER QUESTIONS

Physics

2 answers:

DanielleElmas [232]3 years ago

6 0

Answer:

well for me I think

Explanation:

The use of carbon 12 to tell the age of substances

gregori [183]3 years ago

4 0

"Radiocarbon dating is a method for determining the age of an object containing organic material by using the properties of radiocarbon."

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Refer to science 10 (mirror mirror on the wall)how do the height and width of the object compare with the height and width of th

Irina-Kira [14]

Depends on what type of mirror that is. I am going to assume this is a plain mirror (from the phrase), which means the height and width of the object and image is exactly the same.

6 0

3 years ago

Here's a question from ~ [ AIEEE 2002 ]

lyudmila [28]

r=150m
coefficient of friction= $\mu$ =0.6

As car is avoid skidding

$\\ \sf\hookrightarrow \dfrac{mv^2}{r}=\mu mg$

Cancel m

$\\ \sf\hookrightarrow \dfrac{v^2}{r}=\mu g$

$\\ \sf\hookrightarrow v^2=\mu rg$

$\\ \sf\hookrightarrow v^2=0.6(10)(150)$

$\\ \sf\hookrightarrow v^2=60(150)$

$\\ \sf\hookrightarrow v^2=900$

$\\ \sf\hookrightarrow v=30ms^{-1}$

Done

7 0

2 years ago

Read 2 more answers

You have a stopped pipe of adjustable length close to a taut 62.0 cmcm, 7.25 gg wire under a tension of 4710 NN. You want to adj

Oksana_A [137]

Answer:

6 cm long

Explanation:

F = 4110N

Vo(speed of sound) = 344m/s

Mass = 7.25g = 0.00725kg

L = 62.0cm = 0.62m

Speed of a wave in string is

V = √(F / μ)

V = speed of the wave

F = force of tension acting on the string

μ = mass per unit density

F(n) = n (v / 2L)

L = string length

μ = mass / length

μ = 0.00725 / 0.62

μ = 0.0116 ≅ 0.0117kg/m

V = √(F / μ)

V = √(4110 / 0.0117)

v = 592.69m/s

Second overtone n = 3 since it's the third harmonic

F(n) = n * (v / 2L)

F₃ = 3 * [592.69 / (2 * 0.62)

F₃ = 1778.07 / 1.24 = 1433.927Hz

The frequency for standing wave in a stopped pipe

f = n (v / 4L)

Since it's the first fundamental, n = 1

1433.93 = 344 / 4L

4L = 344 / 1433.93

4L = 0.2399

L = 0.0599

L = 0.06cm

L = 6cm

The pipe should be 6 cm long

6 0

3 years ago

13) A mass attached to the free end of a spring executes simple harmonic motion according to the equation y = (0.50 m) sin (18π

Kitty [74]

Hi there!

The period is given by:

$T = \frac{2\pi}{w}$

T = Period (sec)

w = angular frequency (rad/sec)

According to the equation for SHM in terms of position:

y(t) = Asin(ωt + φ)

A = Amplitude (m)

ω = angular frequency (rad/sec)

t = time (sec)

φ = phase angle

In this instance, the angular frequency is given as 18π.

Plug this value into the equation for T:

$T= \frac{2\pi}{18\pi} = \frac{1}{9} = \boxed{0.111 s}$

4 0

3 years ago

Jack (mass 59.0 kg ) is sliding due east with speed 8.00 m/s on the surface of a frozen pond. He collides with Jill (mass 47.0 k

Phantasy [73]

Answer:

Part(A): The magnitude of Jill's final velocity is $\bf{6.59~m/s}$ .

Part(B): The direction is $\bf{42.7^{0}}$ south to east.

Explanation:

Given:

Mass of Jack, $m_{1} = 59.0~Kg$

Mass of Jill, $m_{2} = 47..0~Kg$

Initial velocity of Jack, $v_{1i} = 8.00~m/s$

Initial velocity of Jill, $v_{2i} = 0$

Final velocity of Jack, $v_{1f} 5.00~m/s$

The final angle made by Jack after collision, $\alpha = 34.0^{0}$

Consider that the final velocity of Jill be $v_{2f}$ and it makes an angle of $\beta$ with respect to east, as shown in the figure.

Conservation of momentum of the system along east direction is given by

$~~~~&& m_{1}v_{1i} + m_{2}v_{2i} = m_{1}v_{1f} \cos \alpha + m_{2}v_{2f}^{x}\\&or,& v_{2f}^{x} = \dfrac{m_{1}(v_{1i} - v_{1f} \cos \alpha)}{m_{2}}$

where, $v_{2f}^{x}$ is the component of Jill's final velocity along east. The direction of this component will be along east.

Substituting the value, we have

$v_{2f}^{x} &=& \dfrac{(59.0~Kg)(8.00~m/s - 5.00 \cos 34.0^{0}~m/s)}{47.0~Kg}\\~~~~~&=& 4.84~m/s$

Conservation of momentum of the system along north direction is given by

$~~~~&& v_{2f}^{y} + v_{1f} \sin \alpha = 0\\&or,& v_{2f}^{y} = - v_{1f} \sin \alpha = (8.00~m/s) \sin 34^{0} = 4.47~m/s$

where, $v_{2f}^{y}$ is the component of Jill's final velocity along north. The direction of this component will be along the opposite to north.

Part(A):

The magnitude of the final velocity of Jill is given by

$v_{2f} &=& \sqrt{(v_{2f}^{x})^{2} + (v_{2f}^{y})^{2}}\\~~~~~&=& 6.59~m/s$

Part(B):

The direction is given by

$\beta &=& \tan^{-1}(\dfrac{4.47~m/s}{4.84~m/s})\\~~~~&=& 42.7^{0}$

4 0

4 years ago

Hita's Question Bank- CTEVTBaishakh] Q.No. 12 What is radiocarbon dating?VER QUESTIONS​

Hita's Question Bank- CTEVTBaishakh] Q.No. 12 What is radiocarbon dating?VER QUESTIONS