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3 years ago

Turn 8/20 into a fraction and simply it

Mathematics

2 answers:

den301095 [7]3 years ago

8 0

Answer: I got 2/5

Hope it helped

Elena L [17]3 years ago

3 0

It reduces down to 2/5. If you divide 8 by 4, you get 2 for the numerator. If you divide 20 by 4, you get 5 for the denominator.

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F(x) = 4x − 12 <br><br> f−1(x) =___? x +____?

natali 33 [55]

Answer:

$f^{-1}(x)=\frac{1}{4}x+3$

Step-by-step explanation:

We have been given the function $f(x)=4x-12$

Below are steps for finding the inverse of the function.

Step 1:

Replace f(x) with y

$y=4x-12$

Step 2:

Interchange x and y

$x=4y-12$

Step 3:

Solve for y

$x+12=4y\\\\y=\frac{1}{4}x+3$

Step 4:

Replace y with $f^{-1}(x)$

$f^{-1}(x)=\frac{1}{4}x+3$

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3 years ago

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stepladder [879]

Answer:

B, D

Step-by-step explanation:

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3 years ago

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rewona [7]

Answer:

Step-by-step explanation:

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3 years ago

Consider the function f(x) = √5x + 15 for the domain [-3, ∞).Find f-¹(x), where f-1 is the inverse of f.Also state the domain of

Ymorist [56]

Answer: We have to find the inverse function of the following:

$f(x)=\sqrt{5x+15}\rightarrow[-3,\infty)\Rightarrow(1)$

The Inverse of the (1) is as follows:

$\begin{gathered} f(x)=y=\sqrt{5x+15} \\ \\ \text{ Switch: }x\text{ and }y\text{ and solve for }y(x)\text{ } \\ \\ \\ y=\sqrt{5x+15}\rightarrow x=\sqrt{5y+15} \\ \\ \\ x^2=5y+15 \\ \\ \\ x^2-15=5y \\ \\ \\ y=\frac{x^2}{5}-\frac{15}{5} \\ \\ \\ \\ y=f^{-1}(x)=\frac{x^2}{5}-3 \\ \\ \\ f^{-1}(x)=\frac{x^{2}}{5}-3 \end{gathered}$

The domain of the inverse function is:

$x\in(-\infty,+\infty)$

3 0

1 year ago

1 more pls helppppppp

Stella [2.4K]

Answer:

A? I think but also it may not be but that's what I think good luck

7 0

3 years ago