Answer:

Explanation:
given,
mass of the car,m = 0.2 Kg
height to width of ramp, y/x = 12/75
initial displacement, L_i = 2.25 m
change in momentum, Δp = 0.58 kg.m/s
distance of change in direction of the ramp, L_f = ?
Using equation

inserting all the values




The car will cost back up to the distance of 0.0196 m
Answer:
a) a = 7.72 m / s², N = 19.9 N and b) F = 25.5 N
Explanation:
To solve this problem we will use Newton's second law, let's set a reference system with an axis parallel to the plane and gold perpendicular axis. Let's break down the weight (W)
sin52 = Wx / W
cos52 = Wy / W
Wx = W sin52
Wy = w cos 52
Let's write them equations
X axis
Wx = ma
Y Axis
N-Wy = 0
N = Wy
a) Let's calculate the acceleration
a = W sin52 / m = mg sin 52 / m
a = g sin 52
a = 9.8 sin52
a = 7.72 m / s²
The force of the ramp is normal
N = Wy = mg cos 52
N = 3.3 9.8 cos 52
N = 19.9 N
b) For the block to move at constant speed the sum of force on the axis must be zero,
F - Wx = 0
F = Wx
F = mg sin52
F = 3.3 9.8 sin 52
F = 25.5 N
Parallel to the plane and going up
Answer:
<h3>
Young modulus of elasticity for a gas is</h3><h2>
<em>Zero</em></h2>
Explanation:
<em>As</em><em> </em><em>the</em><em> </em><em>gas</em><em> </em><em>doesn't</em><em> </em><em>undergo</em><em> </em><em>any</em><em> </em><em>chan</em><em>g</em><em>es</em><em> </em>
<em>so</em><em> </em><em>the</em><em> </em><em>young</em><em> </em><em>modules</em><em> </em><em>of</em><em> </em><em>gas</em><em> </em><em>is</em><em> </em><em>not</em><em> </em><em>defined</em><em>.</em><em>.</em><em>.</em>
B. In step 3
They incorrectly solved for x. It should have been x=-3 and x=5