Question

A plane has a takeoff speed of 88.3 m/s and can accelerate at a rate of 3m/s to reach that speed. How long does the plane take to take-off.

Answer 1

v = $\frac{d}{t}$

and

a = $\frac{v}{t}$

We have acceleration and velocity so:

3 = $\frac{v}{t}$

88.3 = $\frac{d}{t}$

In the acceleration equation we can isolate for v and then plug it back into the other equation to solve...

So...

$3t = v$

$88.3 = 3t$

Divide by three and

t = 29.4 s