3 years ago

At what angle should an object be thrown so that the maximum range is equal to three times the height reached by the projectile?

1 answer:

5 0

This link might help you: https://www.quora.com/At-what-angle-to-the-horizontal-should-a-body-be-projected-so-that-maximum-height-reached-is-equal-its-horizontal-range

You might be interested in

What force keeps our atmosphere from floating out into space?

Tems11 [23]

The answer is C, gravity

4 0

2 years ago

Read 2 more answers

Clutter is _______. annoying frustrating death

Sindrei [870]

Answer: _____= beautiful, yet annoying frustrating death

Explanation:

3 0

3 years ago

Read 2 more answers

A small balloon is released at a point 150 feet away from an observer, who is on level ground. If the balloon goes straight up a

Elza [17]

Answer:

$\dfrac{dz}{dt}=0.65\ ft/s$

Explanation:

Given that

x= 150 ft

$\dfrac{dy}{dt}= 7\ ft/s$

y= 14 ft

From the diagram

$z^2=x^2+y^2$

When ,x= 150 ft and y= 14 ft

$z^2=150^2+14^2$

$z=\sqrt{150^2+15^2}$

z=150.74 ft

$z^2=x^2+y^2$

By differentiating with respect to time t

$2z\dfrac{dz}{dt}= 2x\dfrac{dx}{dt}+2y\dfrac{dy}{dt}$

$z\dfrac{dz}{dt}= x\dfrac{dx}{dt}+y\dfrac{dy}{dt}$

Here x is constant that is why

$\dfrac{dx}{dt}=0$

$z\dfrac{dz}{dt}= y\dfrac{dy}{dt}$

Now by putting the values in the above equation we get

$150.74\times \dfrac{dz}{dt}=14\times 7$

$\dfrac{dz}{dt}=\dfrac{14\times 7}{150.74}\ ft/s$

$\dfrac{dz}{dt}=0.65\ ft/s$

Therefore the distance between balloon and observer increasing with 0.65 ft/s.

5 0

3 years ago

What causes an object to move, change direction or change speed?

Wittaler [7]

I believe it would be an unbalanced force. Because the forces are unbalanced, one side is stronger and, therefore, the object will move.

7 0

2 years ago

Read 2 more answers

PLS SOMEONE HELP QUICK

SVETLANKA909090 [29]

Answer:

the rates of rock formation are similar. i could be wrong tho.....

Explanation:

6 0

2 years ago

Read 2 more answers