Increase the force on the object
The time for the police car to catch up with the speeding motorist is 7.6 seconds.
<h3>What time will the police car catch up with the speeding motorist?</h3>
The police car and the motorist will cover equal distances.
Let the distance covered be d.
Distance covered by the motorist = speed * time
time = t, speed = 30 m/s
d = 30t
Distance covered by the police car = acceleration * (time)
time = t - 2, acceleration = 5.0 m/s²
d = 5(t-2)²
d = 5(t² - 4t + 4)
d = 5t² - 20t + 20
Equating the two equations for distance
5t² - 20t + 20 = 30t
5t² - 50t + 20 = 0
Solving for t using the quadratic formula:
t = 9.6 second or 0.4 seconds
Since t > 2, t = 9.6 seconds
t - 2 = 9.6 - 2
t - 2 = 7.6 seconds
Therefore, the time for the police car to catch up with the speeding motorist is 7.6 seconds.
Learn more about distance and acceleration at: brainly.com/question/14344386
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Well basically in physics and chemistry, the law of conservation of energy states that the total energy of an isolated system remains constant, it is said to be conserved over time. This law means that energy can neither be created nor destroyed, it can only be transformed or transferred from one form to another.
Hope this helps (:
Explanation:
The range <em>R</em> of a projectile is given by

The maximum range
occurs when
. Let
be the angle above or below 45°. Now let's look at the ranges brought about by these angle differences.
<u>Case</u><u> </u><u>1</u><u>:</u><u> </u><u>A</u><u>ngle</u><u> </u><u>above</u><u> </u><u>4</u><u>5</u><u>°</u>
We can write the range as



<u>Case</u><u> </u><u>2</u><u>:</u><u> </u><u>Angle</u><u> </u><u>below</u><u> </u><u>45</u><u>°</u>
We can write the range as



Note that the equations (1) and (2) are identical. Therefore, the ranges are equal if they differ from 45° by the same amount.
Answer:
A wave is a disturbance that carries energy from one place to another.
Explanation: